Lunar phases include the waxing and waning phases. The waxing phases have light on the _______ side of the moon as we look at it
1 answer:
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Answer:
22.81 g
Explanation:
Given that:
Pressure = 1.68 atm
Temperature = 46 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (46 + 273.15) K = 319.15 K
Volume = 8.99 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
1.68 atm × 8.99 L = n × 0.0821 L.atm/K.mol × 319.15 K
<u>⇒n = 0.5764 moles </u>
Given that :
Amount of methane = 4.88 g
Molar mass = 16.04 g/mol
The formula for the calculation of moles is shown below:
Thus,
<u>Moles of Krypton = Total moles - Moles of methane = 0.5764 - 0.3042 moles = 0.2722 moles</u>
Also, Molar mass of krypton = 83.798 g/mol
So,
The formula for the calculation of moles is shown below:
Thus,
<u>Mass of krypton = 22.81 g</u>
Answer:
Here's what I get
Explanation:
The reaction is an E1 elimination of an alcohol to form an alkene. It has three steps:
1. Protonation
The alcohol is protonated with aqueous sulfuric acid to convert it into a better leaving group.
2. Loss of the leaving group
A water molecule leaves in a unimolecular process to form a stable 3° carbocation.
3. Loss of an α-hydrogen
A water molecule removes an α-hydrogen, forming 2-methylpropene and regenerating the original hydronium ion.
