Answer:
see below (upper left)
Step-by-step explanation:
When the x-values are sequential, a linear function will have y-values that differ by the same amount.
The upper left table has y-values that differ by -2.
The upper right table has y-values that differ by 2, -6, 2. These values are not the same.
The lower left table has y-values that differ by -1, 5, -13. These values are not the same.
The lower right table has y-values that differ by 1, 3, 5. These values are not the same.*
__
The upper left table represents a linear function.
_____
* The <em>2nd</em> differences are a constant 2, so this table represents a <em>2nd</em>-degree polynomial.
Answer:
58
Step-by-step explanation:
PEMDAS
If the "some number" is represented by m, then "some number cubed" is m^3. The product of that and 2 is 2m^3. Eight more than that product is
.. 8 +2m^3 . . . . . . . . upper-left selection
Answer:
A. Louisa made an error when determining the original solution of x = 56.
Step-by-step explanation:
1/4x - 3 = 3/8x + 4
To verify x=56 is a solution, substitute x=56 into the equation
1/4(56) - 3 = 3/8(56) + 4
Multiply
14 -3 = 21 +4
Combine like terms
11 = 25
The steps are correct.
x=56 must not be a solution to the equation
Answer:
Yes, you can
Step-by-step explanation:
As a point of reference, assume the equation is:
![y = 5x](https://tex.z-dn.net/?f=y%20%3D%205x)
Where
![y = total\ cost](https://tex.z-dn.net/?f=y%20%3D%20total%5C%20cost)
and
![x = pounds](https://tex.z-dn.net/?f=x%20%3D%20pounds)
In standard unit of conversion:
![1\ pound = 0.4793\ quart](https://tex.z-dn.net/?f=1%5C%20pound%20%3D%200.4793%5C%20quart)
So:
![x\ pounds = 0.4793x\ quart](https://tex.z-dn.net/?f=x%5C%20pounds%20%3D%200.4793x%5C%20quart)
Substitute 0.4793x for x in ![y = 5x](https://tex.z-dn.net/?f=y%20%3D%205x)
![y = 5 * 0.4793x](https://tex.z-dn.net/?f=y%20%3D%205%20%2A%200.4793x)
![y = 2.3965x](https://tex.z-dn.net/?f=y%20%3D%202.3965x)
The above equation is the equivalent of
in quarts
<em>So, irrespective of what the equation is, you can always substitute quarts into the equation.</em>