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2 years ago

15

Please please help i’ll give brainliest tysm :)

2 answers:

Galina-37 [17]2 years ago

8 0

Answer:

4,400 yards

Step-by-step explanation:

2.5 x 1,760

Sergio [31]2 years ago

5 0

4,400

you multiply 1760 by 2.5

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Someone buys a pen for 1.09 and paper for 2.50 how much more does the paper cost more then the pen

maks197457 [2]

Answer:1.41

Step-by-step explanation: subtraction

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2 years ago

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rewona [7]

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2 years ago

Can some one do this for me

Mama L [17]

Answer:

1)13(left)

2)52(right)

3)48

4)51.923

Step-by-step explanation:

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3 years ago

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Currently 1 United States dollar equals 19.25 Mexican pesos. If you exchanged 725 Mexican pesos for US dollars, what amount woul

Irina18 [472]

Answer:

The value of 725 Mexican pesos is equals to 37.66 US dollars

Step-by-step explanation:

Given as :

The value of 1 US dollar equals to 19.25 Mexican pesos

The total amount of Mexican pesos = 725

Now,

∵ 19.25 Mexican pesos equals to 1 US dollars

∴ 725 Mexican pesos equals to $\frac{725}{19.25}$ = 37.66 US dollars

Hence The value of 725 Mexican pesos is equals to 37.66 US dollars Answer

5 0

3 years ago

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

6 0

3 years ago