Answer:
I am pretty sure it is B
Step-by-step explanation:
:)
Answer:
"The product of a rational number and an irrational number is SOMETIMES irrational." If you multiply any irrational number by the rational number zero, the result will be zero, which is rational. Any other situation, however, of a rational times an irrational will be irrational
A better statement would be:
"The product of a non-zero rational number and an irrational number is irrational
Answer:
The percent of the people who tested positive actually have the disease is 38.64%.
Step-by-step explanation:
Denote the events as follows:
<em>X</em> = a person has the disease
<em>P</em> = the test result is positive
<em>N</em> = the test result is negative
Given:

Compute the value of P (P|X) as follows:

Compute the probability of a positive test result as follows:

Compute the probability of a person having the disease given that he/she was tested positive as follows:

The percentage of people having the disease given that he/she was tested positive is, 0.3864 × 100 = 38.64%.
The correct answer is A because the 4 in the X value repeats two time and on the other ones doesn't