CH4 + 2O2 =======> CO2 + 2H2O
Answer:
4.1 mol·L⁻¹
Explanation:
You are diluting the solution with water, so you can use the dilution formula
c₁V₁ = c₂V₂ Divide each side by V₂
c₂ = c₁ × V₁/V₂
Data:
c₁ = 7.0 mol·L⁻¹; V₁ = 2.5 L
Water added = 1.5 L
Calculations:
(a) <em>New volume
</em>
V₂ = 2.5 L + 1.8 L
= 4.3 L
(b) <em>New concentration
</em>
c₂ = 7.0 × 2.5/4.3
= 7.0 × 0.581
= 4.1 mol·L⁻¹
Hello there!
When you burn the wood, some of the mass will go off as smoke. So, in a closed environment, the total mass of the area will stay the same, but the wood's mass will not.
I hope this helps!
Brady
