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ale4655 [162]
3 years ago
15

Find the volume of a gas at standard pressure if its volume at 1.9 atm is 80 ml?

Chemistry
1 answer:
kogti [31]3 years ago
6 0

Answer:

1.5 × 10² mL

Explanation:

Step 1: Given data

  • Initial pressure of the gas (P₁): 1.9 atm
  • Initial volume of the gas (V₁): 80 mL
  • Final pressure of the gas (P₂): 1.0 atm (standard pressure)
  • Final volume of the gas (V₂): ?

Step 2: Calculate the final volume of the gas

For an ideal gas, we can calculate the final volume of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 1.9 atm × 80 mL/1.0 atm

V₂ = 1.5 × 10² mL

Since the pressure decreased, the volume of the gas increased.

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3 years ago
A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som
irinina [24]

Answer:

m_{KBr}=6.030gKBr

Explanation:

Hello.

In this case, since the normal boiling point of X is 117.80 °C, the boiling point elevation constant is 1.48 °C*kg*mol⁻¹, the mass of X is 100 g and the boiling point of the mixture of X and KBr boils at 119.3 °C, we can use the following formula:

(T_b-T_b_0)=i*m*K_b

Whereas the Van't Hoff factor of KBr is 2 as it dissociates into potassium cations and bromide ions; it means that we can compute the molality of the solution:

m=\frac{T_b-T_b_0}{i*K_b}=\frac{(119.3-117.8)\°C}{2*1.48\°C*kg*mol^{-1}}\\  \\m=0.507mol/kg

Next, given the mass of solventin kg (0.1 kg from 100 g), we compute the moles KBr:

n_{KBr}=0.507mol/kg*0.1kg=0.0507mol

Finally, considering the molar mass of KBr (119 g/mol) we compute the mass that was dissolved:

m_{KBr}=0.0507mol*\frac{119g}{1mol} \\\\m_{KBr}=6.030gKBr

Best regards.

3 0
3 years ago
How are scientific questions answered?
Katena32 [7]

Answer:

They're answered by having an equation and the some symbols with it to make the answer more correct.

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