Here, given-
homozygous alleles 'a' have a frequency of 0.3.
Also the alleles are in equilibrium in a Hardy-Weinberg population. The frequency of individuals that are homozygous for this allele are= 0.49.
The Hardy-Weinberg equilibrium can be defined as the principle which states that the variation in the genetic makeup of a population remains constant and unchanged till there are no external interferences, influencing the population.
Calculation-
Then to find the frequency of the individuals homozygous for this allele the following formula needs to be used-
Thus, the individuals homozygous for the allele can be calculated by 
Learn more about the Hardy-Weinberg equilibrium here-
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Answer:
~3 times...
Explanation:
Well...the data provided by different institutes of oncology were highly random both in US and Hungary. but by using Chi-Square probability analysis in both of the countries the ration comes as 2.87:1 that means residents of US are 3 times more likely to die from breast cancer than Hungarians. A 5% confidence interval was used in this test with percentages 31.8% for us and 11.9% for Hungarians.
Answer:
a .carbon dioxide(Co2) and water (H2O)
b. air and soil
Explanation:
During photosynthesis, plants take in carbon dioxide (CO2) and water (H2O) from the air and soil. Within the plant cell, the water is oxidized, meaning it loses electrons, while the carbon dioxide is reduced, meaning it gains electrons. This transforms the water into oxygen and the carbon dioxide into glucose.
