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Nostrana [21]
3 years ago
9

16,000 lb= __ T 3 lb= __oz lb= pounds T=tons OZ=ounce

Mathematics
2 answers:
ololo11 [35]3 years ago
5 0
8 tons
48 ounces
Hoped I helped if I did say thanks
Anna71 [15]3 years ago
4 0
8 tons
48 ounces
Hope this helped
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Solve y=f(x) for x. Then find the input when the output is -3.
DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(x-5\right)^3-1

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

\:\:y=\:\left(x-5\right)^3-1

-3\:=\:\left(x-5\right)^3-1\:\:\:

switch sides

\left(x-5\right)^3-1=-3

Add 1 to both sides

\left(x-5\right)^3-1+1=-3+1

\left(x-5\right)^3=-2

\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

Thus, the input values are:

x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}

And the real input is:

x=-\sqrt[3]{2}+5

  • x=3.74
4 0
3 years ago
Please help me out on all of these !! Thank you
MakcuM [25]

Answer:

A. $110.00

B. ???

C. $83.00

D. 37 Day's

8 0
3 years ago
Please answer number 15 and 17​
il63 [147K]

Answer:

15 ans rln 1 and 17 ans rln3

7 0
3 years ago
The formula F=95(K−273.15)+32 converts a temperature from kelvin K to degrees Fahrenheit
DENIUS [597]

F=95(K−273.15)+32

Switch the equation so that F is on the right side:

95(K−273.15)+32 = F

Use the distributive property:

95K + 95(-273.15) + 32 = F

95K - 25949.25 + 32 = F

95K - 25917.25 = F

Add 25917.25 to both sides:

95K = 25917.25 + F

Divide each term by 95:

K = 25917.25 / 95 + F/95


K = (25917.25 + F) /95



7 0
3 years ago
1) This is using symbols to represent algebraic relationships between quantities.
Agata [3.3K]

Answer:

variables i believe would be the answer

Step-by-step explanation:

6 0
3 years ago
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