Let's call your speed "a"
her walking speed is then "2a"
and her friend's scooter speed is 10 a
let's also call the distance you need to walk "d"
so the time (t)you need is:
d/t=a
t=d/a
and her time is:
t=

(half a distance with the speed of 2a and half a distance (d/2) with the distance of 10 a
now we count (we know that her time is 30 minutes)
30=

//multiply by 20a
600a=

600a=6d/divide by 6
100a=d
Now, in order to calculate your time we need to calculate:
t=d/a
but we know how much is d now!
t=

=100
which means that you need 100 minutes, or 1 h 40 minutes!!!
Answer:
Step-by-step explanation:
<u>Given equations:</u>
<u>Add together:</u>
- -8x + 8y + 3x - 8y = 8 - 18
- - 5x = - 10
Correct option is D
Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
<u><em>To cover a rectangular region of her yard, Penny needs at least 170.5 square feet of sod. The length of the region is 15.5 feet. What are the possible widths of the region?</em></u>
<u><em></em></u>
<u><em>L=length=15.5 ft; W=width; A=area=>170.5 sq ft</em></u>
<u><em></em></u>
<u><em>L*W=>170.5 sq ft Divide each side by L</em></u>
<u><em></em></u>
<u><em></em></u>
<u><em>W=>170.5 sq ft/L</em></u>
<u><em></em></u>
<u><em>W=>170.5 sq ft/15.5 ft=>11 feet</em></u>
<u><em></em></u>
ANSWER: To cover at least 170.5 sq ft. the width must be at least 11 feet.
<h2><em><u>
Brainly pls</u></em></h2>