To solve this problem we will apply the concepts related to energy conservation. With this we will find the speed before the impact. Through the kinematic equations of linear motion we will find the velocity after the impact.
Since the momentum is given as the product between mass and velocity difference, we will proceed with the velocities found to calculate it.
Part A) Conservation of the energy
Part B) Kinematic equation of linear motion,
Here
v= 0 Because at 1.5m reaches highest point, so v=0
Therefore the velocity after the collision with the floor is 3.7m/s
PART C) Total change of impulse is given as,
force is mass * acceleration
so 2kg * 2m/s^2 = 4 N
Answer:
11.025 m
87.75 m
Explanation:
Time of flight(T) of a projectile = 2U(sin∅)/g
Where U = initial Velocity, g = acceleration due to gravity, ∅= angle of projection.
Make ∅ the subject of the the equation,
∅ = sin⁻¹[(T× g)/2U]
Where U = 15m/s, T= 3.0 s, g = 9.8 m/s²
∅ = sin⁻¹[(3 × 9.8)/(2×15)]
∅ = sin⁻¹(29.4/30)
∅= sin⁻¹(0.98) = 78.52°
Using the formula for maximum height of a projectile
H = U²sin²∅/2g
H = 15²(sin²78.52)/2 × 9.8
H = 225(0.98 × 0.98)/19.6
H = 216.09/19.6
H = 11.025 m
Range (R) = U²sin2∅/g
R = 15²sin(2×79.52)/9.8
R = 225(0.39)
R =87.75 m
∵ the building is = 11.025 m tall and the base of the building is 87.75m away from where the stone landed.
Answer:
B. 2 Hours
Explanation:
If you are going 45 miles per hour, you will travel 45 miles in 1 hour. It will take you 2 hours to travel 90 miles at a speed of 45 miles per hour.
