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Stella [2.4K]
3 years ago
14

An arrow is launched with an initial velocity of 7.6 m/s at an angle of 42 degrees above the horizontal. What is the horizontal

component of the velocity at the highest point of the trajectory?
Physics
1 answer:
AleksAgata [21]3 years ago
5 0

Explanation:

At any point on the arrow's trajectory, the horizontal component of the velocity is the same. Therefore, the horizontal component of the velocity at the top of its trajectory is

v_x = v_{0x} = v_0\cos{42°} = (7.6\:\text{m/s})\cos{42°}

\:\:\:\:\:=5.6\:\text{m/s}

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b: false

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It's true that endothermic reactions absorb heat from their surrounding.  But this makes the surroundings cooler, not warmer.

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A word that means to squeeze a gas in to a smaller place
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A 3.0-kg object moves to the right with a speed of 2.0 m/s. It collides in a perfectly elastic collision with a 6.0-kg object mo
Zinaida [17]

Answer:

The kinetic energy of the system after the collision is 9 J.

Explanation:

It is given that,

Mass of object 1, m₁ = 3 kg

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Mass of object 2, m₂ = 6 kg

Speed of object 2, v₂ = -1 m/s (it is moving in left)

Since, the collision is elastic. The kinetic energy of the system before the collision is equal to the kinetic energy of the system after the collision. Let it is E. So,

E=\dfrac{1}{2}m_1v_1^2+\dfrac{1}{2}m_2v_1^2

E=\dfrac{1}{2}\times 3\ kg\times (2\ m/s)^2+\dfrac{1}{2}\times 6\ kg\times (-1\ m/s)^2

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So, the kinetic energy of the system after the collision is 9 J. Hence, this is the required solution.

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In a candy factory, the nutty chocolate bars contain 20.0 % pecans by mass. If 4.0 kg of pecans were used for candy last Tuesday
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Answer:

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We got that 20 % of the mass of a nutty chocolate bar its pecans, if 4.0 kg of pecans were used, we need to find the X in the equation

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X = 4.0 kg / 0.2

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Of course, we need the total mass produced in pounds, and not in kilograms.  Looking at an conversion table, we can find that 1 kg its 2.20462 pounds, multiplying the value for total mass produced by the conversion factor we get:

X = 20.0 \ kg * 2.20462 \ \frac{pounds}{kg}

X = 44.0924 \ pounds

Now, we just need to round off to two significant figures. This is:

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