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evablogger [386]
3 years ago
11

A 1.5kw vacuum cleaner is used for half an hour. Calculate its energy usage.​

Physics
1 answer:
juin [17]3 years ago
8 0

Answer:

its energy usage is 0.05

Explanation:

1.5kw/30=0.05

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What part of the bacterial cell helps it stick to surfaces
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3 years ago
A person drives 20 miles north and 45 miles east. What is the angle of the resultant straight to their destination?
Alex787 [66]
Let us take east and north as the positive x and y-axes should the motion be plotted in a cartesian plane. Thus, the x value is 45 miles and the y value is 20. The tangent of an angle is equal to the ratio of y to x.

   tanθ = y / x

Substituting,

   tanθ = 20/45 = 0.44

The value of θ is 23.96°.
7 0
3 years ago
A grandfather clock depends on the period of a pendulum to keep correct time.(ii) Suppose a grandfather clock is calibrated corr
ANEK [815]

The grandfather clock will now run slow (Option A).

<h3>What is Time Period of an oscillation?</h3>
  • The time period of an oscillation refers to the time taken by an object to complete one oscillation.
  • It is the inverse of frequency of oscillation; denoted by "T".

Now,

  • \sqrt{\frac{L}{g}}, where L is the length and g is the gravitational constant, is the formula for a pendulum's period.
  • The period will increase as one climbs a very tall mountain because g will slightly decrease.
  • Due to this and the previous issue, the clock runs slowly and it seems that one second is longer than it actually is.

Hence, the grandfather clock will now run slow (Option A).

To learn more about the time period of an oscillation, refer to the link: brainly.com/question/26449711

#SPJ4

6 0
1 year ago
what is the electric potential at point A in the electric field created by a point charge of 5.5 • 10^-12 C? estimate k as 9.00
Hitman42 [59]

The electric potential at point A in the electric field= 0.099 x 10 ⁻¹v

<u>Explanation</u>:

Given data,

charge = 5.5 x 10¹² C

k =9.00 x 10⁹

The electric potential V of a point charge can found by,

V= kQ / r

Assuming, r=5.00×10⁻² m

V= 5.5 x 10⁻¹²C x  9.00 x 10⁹ / 5.00×10⁻² m

V=  49.5 x 10⁻³/ 5.00×10⁻²

Electric potential V=  0.099 x 10⁻¹v

3 0
3 years ago
Help please!!!!!!!!!!​
mrs_skeptik [129]

Answer:

j

Explanation:

6 0
3 years ago
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