Her speed was 7.27 meters per second
write out what you have on both sides, then just use basic multiplication to try and even out both sides. I can help if you need me to balance some for you!!
1 kilometre is equal to 1000m
and 4.1 minutes is equal to 246 seconds
thus 1000/246 = 4.065 m/s
and the direction is towards the west
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vo = 25 m/sec
<span>vf = 0 m/sec </span>
<span>Fμ = 7100 N (Force due to friction) </span>
<span>Fg = 14700 N </span>
<span>With the force due to gravity, you can find the mass of the car: </span>
<span>F = ma </span>
<span>14700 N = m (9.8 m/sec²) </span>
<span>m = 1500 kg </span>
<span>Now, we can use the equation again to find the deacceleration due to friction: </span>
<span>F = ma </span>
<span>7100 N = (1500 kg) a </span>
<span>a = 4.73333333333 m/sec² </span>
<span>And now, we can use a velocity formula to find the distance traveled: </span>
<span>vf² = vo² + 2a∆d </span>
<span>0 = (25 m/sec)² + 2 (-4.73333333333 m/sec²) ∆d </span>
<span>0 = 625 m²/sec² + (-9.466666666667 m/sec²) ∆d </span>
<span>-625 m²/sec² = (-9.466666666667 m/sec²) ∆d </span>
<span>∆d = 66.0211267605634 m </span>
<span>∆d = 66.02 m</span>
Answer:
e. Only(a) and (b) above are correct
Explanation:
Impulse
= Fx t = m ( v-u )
v-u = change in velocity
F x t = mass x change in velocity
change in velocity = F t / mass
=a t
change in velocity ∝ t ( time ) , if a is constant
dv = a_avg dt
∫dv = a_avg ∫dt
v-u = a_avg t
change in velocity ∝ t ( time )
So both (a) and (b) are correct.