Answer: Children tickets cost 7.50
Adult tickets cost 12.50
Step-by-step explanation:
Let a represent adult tickets
Let c represent child tickets
On the first day she sells 6 adult tickets and 5 children tickets for total of 112.50. This can be written as:
6a + 5c = 112.50 ...... equation i
On the second day she sells 8 adult tickets and 4 children tickets for the total 130. This can be written as:
8a + 4c = 130 ....... equation ii
6a + 5c = 112.50 ...... equation i
8a + 4c = 130 ....... equation ii
Multiply equation i by 4
Multiply equation ii by 5
24a + 20c = 450 ........ equation iii
40a + 20c = 650 ......... equation iv
Subtract iii from iv
16a = 200
a = 200/16
a = 12.50
Adult tickets cost 12.50
From equation ii,
8a + 4c = 130
8(12.50) + 4c = 130
100 + 4c = 130
4c = 130 - 100
4c = 30
c = 30/4
c = 7.50
Children tickets cost 7.50
To determine the ratio that would perfectly illustrate the given above, we need to have these numbers such that they would have the same unit. It is to be noted that every year is composed of 12 months. Converting 24 months to years,
n = (24 months)(1 year/12 months) = 2 years
Hence, the ration should be 2 years is to 3 years which is equal to 2:3.
Answer: 2:3
Answer:
20 meters square
Step-by-step explanation:
Surface Area of this square based pyramid = A = base area + 4* (face area)
A = (2 *2) + 4* ( (1/2)*2 * 4) )
A = 4 + 4*(4)
A = 4 + 16 = 20
A = 20 square meters
Answer:
9. (7a + 6b – 9c) – (3a – 6c)
=7a+6b-9c-3a+6c
=7a-3a+6b-9c+6c
=4a+6b-3c
10. (x2 – 9) – (-2x2 + 5x – 3)
= x^2-9+2x^2-5x+3
=x^2+2x^2-5x-9+3
=3x^2-5x-6
11. (5 – 6d – d2) – (-4d – d2)
=5-6d- d^2+4d+ d^2
=5-6d+4d-d^2+ d^2
=5-2d
12. (-4x + 7) – (3x – 7)
=-4x+7-3x+7
= -4x-3x+7+7
=-7x+14
13. (4a – 3b) – (5a – 2b)
=4a-3b-5a+2b
=4a-5a-3b+2b
= -a-b
14. (2c + 3d) – (-6d – 5c)
=2c+3d+6d+5c
=2c+5c+3d+6d
=7c+9d
15. (5x2 + 6x – 9) – (x2 – 3x +7)
=5x^2+6x-9- x^2+3x-7
=5x^2- x^2+6x+3x-9-7
=4x^2+9x-16
16. (3y – 6) – (8 – 9y)
=3y-6-8+9y
=3y+9y-6-8
=12y-14
17. (3a2 – 2ab + 3b2) - (-a2 – 5ab + 3b2)
=3a^2-2ab+3b^2+ a^2+5ab-3b^2
=3a^2+ a^2-2ab+5ab+3b^2- 3b^2
=4a^2+3ab
18. 5c – [8c – (6 – 3c)]
=5c-[8c-6+3c]
=5c-8c+6-3c
=5c-8c-3c+6
= -6c+6
19. 10x + [3x – (5x – 4)]
=10x+[ 3x-5x+4]
=10x+3x-5x+4
=8x+4
20. 3x 2 – [7x- (4x – x2) + 3]
=3x^2-[7x-4x+ x^2+3]
=3x^2-7x+4x- x^2-3
=3x^2-x^2-7x+4x-3
=2x^2-3x-3
21. x2 – [ - 3x+ ( 4 – 7x)]
= x^2-[ -3x+4-7x]
= x^2+3x-4+7x
= x^2+3x+7x-4
= x^2+10x-4
