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scoray [572]
3 years ago
5

A scientist wants to publish a report on a general feeding habits of a moose in Canada. He should

Physics
2 answers:
saul85 [17]3 years ago
6 0
Observe as many moose as he can in as many locations as possible.
Rom4ik [11]3 years ago
3 0

THE ANSWER IS: <u><em>observe as many moose as he can in as many locations as possible.</em></u>

In order to write a report about general feeding habits of moose over such a large area as Canada, the scientist needs to observe as many moose as he can in as many locations as possible. Studying too few moose or in just one location will not provide enough data to apply his results to all moose in Canada. The scientist can also use studies by other scientists to help in his report.

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Why is atomaspheric pressure greater at the surface on Earth
andrew-mc [135]
Hello!

Because as you get closer to the surface of the earth, the more air that is on top of you. At the top of the atmosphere, there is less air, and everything is a vacuum, where you have no weight. When you get close to the earth, the weight of the air builds until it when you're at the very lowest point of the earths surface, all the air in the atmosphere above you is pressing down.

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3 years ago
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HOW MANY PIES DOSE IT TAKE TO GET TO THE MOON
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3 years ago
Did i draw the tangent line correctly?​
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3 years ago
A woman is running around a playground while keeping an eye on her child who is on a swing set. The child is going back and fort
Nutka1998 [239]

Answer:

(a) 1500 m

(b) 2827.43m

Explanation:

Given that the time for one cycle of the swing is 1 s

The radius of the swing, R= 3.0m

The angle covered, \theta, by each swing is a quarter of the circle. i.e.

\Theta=\frac {\pi}{2}

Speed of running of women =5 m/s.

Time of running = 5 minutes= 5 x 60 secondes= 300 s.

(a) As distance= (speed) x (time)

So, the required distance= 5 x 300 m= 1500 m.

(b) As there are two swings in one cycle, so, the distance covered in one swing is the length of the circular shown in the figure.

As arc length, l= \theta R, where \theta is the angle, in radian, subtended by the arc at the center, and R is the radius of curvature of the arc.

So, the distance covered by the child in 1 swing = \frac {\pi}{2}\times 3 m=\frac{3\pi}{2}m.

In 1 cycle, there are 2 swings, so distance covered in 1 cycle = 3 \pi m.

Now, in 1 second there is 1 cycle, so in 5 minutes there will be 300 cycles.

So, the total distance covered by the child

= 3\pi\times 300 m= 2827.43 m.

3 0
3 years ago
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