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3 years ago

10

Hi guys. Im doing a project at school where we have to create a mouse trap powered car. I wanted to know what materials are a mu

st have to make the car move more than 5 meters?

1 answer:

natta225 [31]3 years ago

4 0

Depends on how heavy ur car is, u could use a high powered fan to move the can or u could use the motor and wheels from a remote control car

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Four forces of magnitude 10N,15N, 4N, 6N act on on object in the direction North West, East and South respectively, find their m

maria [59]

Magnitude 17 root

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3 years ago

Which statement best describes the relationship between mass and gravitational attraction (pull)?

Gnesinka [82]

Answer:

The first option, "The more mass an object has, the greater the gravitational pull. "

Explanation:

Newton's Law of Gravity states that $F_G=\frac{Gm_1m_2}{r^{2}}$ , where G is the gravitational constant, $m_1$ and $m_2$ are the masses of the two objects, and <em>r</em> is the distance between the objects' centers. Because the objects' masses are in the fraction's numerator, they are directly proportional to $F_G$ , and increasing the mass of one or both objects increases the gravitational pull.

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7 0

3 years ago

100 POINTS 100 POINTS 100 POINTS!!!!!<br> HELP PLEASE I DON'T KNOW WHAT TO DO!!!!!

Westkost [7]

Answer:

block 2 or 4

because of the distribution of weight and force being applied to the object

3 0

3 years ago

Read 2 more answers

Suppose that a 1000 kg car is traveling at 25 m/s (aprox 55mph). Its brakes can apply a force of 5000N. What is the minimum dist

Brrunno [24]

Assuming the the car is travelling to the right (→):

$R(\rightarrow), F = ma$

$\implies a = \frac{F}{m}$

$= \frac{-5000}{1000}$

$= -5 \ ms^{-2}$

The information we know:

$u = 25 \ ms^{-1}$

$v = 0$

$a = -5 \ ms^{-2}$

Using one of the equations of motion:

$v^2 = u^2 + 2as$

$\implies s = \frac{v^2 -u^2}{2a}$

$= \frac{0^2 - 25^2}{2\times (-5)}$

$= \frac{625}{10}$

$= 62.5\ m$

8 0

3 years ago

Read 2 more answers

A piston motion moves a 25-kg hammerhead vertically down 1 m from rest to a velocity of 50 m/s in a stamping machine. What is th

Alja [10]

Answer:

31.005 KJ

Explanation:

We are given that

Mass of hammerhead=25 kg

Initial velocity,u=0

Final velocity,v=50 m/s

h=-1 m

h'=0

We have to find the change in total energy of the hammerhead.

Change in total energy= $E_2-E_1=m(u_2-u_1)+\frac{1}{2}m(v^2-u^2)+mg(h-h')$

Using the formula

Change in internal energy of hammerhead= $m(u_2-u_1)=0$

Change in total energy= $\frac{1}{2}(25)(50)^2+25\times 9.8(-1)$

Where $g=9.8m/s^2$

Change in total energy= $31005 J=\frac{31005}{1000}=31.005 KJ$

1 KJ=1000 J

3 0

3 years ago