Answer:
2917.4 m/s
Explanation:
From the question given above, the following data were:
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
Radius (r) of the Moon = 1737 Km
Escape velocity (v) =?
Next, we shall determine the gravitational acceleration of the Moon. This can be obtained as follow:
Gravitational acceleration of the earth = 9.8 m/s²
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
= 0.25 × 9.8 = 2.45 m/s²
Next, we shall convert 1737 Km to metres (m). This can be obtained as follow:
1 Km = 1000 m
Therefore,
1737 Km = 1737 Km × 1000 m / 1 Km
1737 Km = 1737000 m
Thus, 1737 Km is equivalent to 1737000 m
Finally, we shall determine the escape velocity of the rocket as shown below:
Gravitational acceleration of the Moon (g) = 2.45 m/s²
Radius (r) of the moon = 1737000 m
Escape velocity (v) =?
v = √2gr
v = √(2 × 2.45 × 1737000)
v = √8511300
v = 2917.4 m/s
Thus, the escape velocity is 2917.4 m/s
If you are operating a boat and you hear <span>the fog signal of another boat you cannot see, you should immediately reverse the engine or even stop it if you can do that (for the safety of everyone).
Then, you should ask someone else to go to the bow and assist in looking (maybe he/she can see the other boat that you cannot see) </span><span />
Answer:
I do not have enough information to tell
Explanation:
This is deduced due to the fact that if the net force due to B and C on A is zero, the charges on B and C could either be positive or negative depending on the charge on A.
Your answer is going to be 0 degrees Kelvin!
Answer:
hi
<h3>BECAUSE MERCURY IS USED BECAUSE IT is the only liquid available in room temperature </h3>
Explanation:
pls mark as a BRAINLIST
