1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
solniwko [45]
2 years ago
15

How many moles of N2O5 are needed to produce 7.90 g of NO2?

Chemistry
1 answer:
Roman55 [17]2 years ago
4 0

Answer:

0.085 moles of  N₂O₅ are needed

Explanation:

Given data:

Mass of NO₂ produces = 7.90 g

Moles of N₂O₅ needed = ?

Solution:

2N₂O₅       →     4NO₂  + O₂

Number of moles of NO₂ produced :

Number of moles = mass/ molar mass

Number of moles = 7.90 g/ 46 g/mol

Number of moles = 0.17 mol

now we will compare the moles of NO₂   with N₂O₅.

                NO₂          :       N₂O₅

                  4            :          2

                0.17          :         2/4×0.17 = 0.085 mol

Thus, 0.085 moles of  N₂O₅ are needed.

You might be interested in
What is the percent of composition by mass of hydrogen in NH4HCO3 (gram-formualmass=79 grams/mole)?
musickatia [10]
5/79=0.063
0.063 x 100 = 6.3%
5 0
2 years ago
Balance the following chemical
poizon [28]

Answer:

Explanation:

A chemical formula can be defined as a notation that is used to show which element and how many is contained in a chemical compound.

Also, in chemistry, the sum of charges of the anion and the cation of any ionic compound is always equal to zero.

A chemical equation is considered to be balanced when the amount of reactants on the left is equal to the amount of products on the right.

Therefore;

[2]FeBr3 + [3]Na2S → [1]Fe2S3 + [6]NaBr

In the above chemical equation, we will balance the reactants in the chemical equation with the smallest coefficients possible;

2FeBr_{3} + 3Na_{3}S ----> Fe_{2}S{3} + 6NaBr

Two (2) moles of Iron (III) Bromide reacts with two (2) moles of Sodium Sulfide to form Iron (III) Sulfide and Sodium Bromide.

4 0
2 years ago
How is an electron orbital similar to a parabola?
AVprozaik [17]

Answer:

Explained below.

Explanation:

First of all, the orbital path of electron is mostly parabolic in electric field.

In an electric field, electrons behave very similar to a projectile. Thus, Electrons have a parabolic path in an electric field simply because the speed of the electrons in a direction which is perpendicular to the electric field is constant since there is no force. Therefore, there will be no acceleration along that perpendicular direction. However there will be an acceleration that is constant in the direction of the electric field which makes it act in a similar manner to a projectile under gravity.

5 0
3 years ago
How many moles of gas X are present if the gas has a volume of 2dm³ at room temperature and pressure? Give your answer to 2 deci
bezimeni [28]

Answer:

Approximately 0.08\; \rm mol, assuming that this gas is an ideal gas.

Explanation:

Look up the standard room temperature and pressure:25\; \rm ^{\circ}C and P = 101.325 \; \rm kPa.

The question states that the volume of this gas is V = 2\; \rm dm^{3}.

Convert the unit of all three measures to standard units:

\begin{aligned} T &= 25\; \rm ^{\circ}C \\ &= (25 + 273.15)\; \rm K \\ &= 293.15\; \rm K\end{aligned}.

\begin{aligned}P &= 101.325\; \rm kPa \\ &= 101.325 \; \rm kPa \times \frac{10^{3}\; \rm Pa}{1\; \rm kPa} \\ &= 1.01325 \times 10^{5}\; \rm Pa\end{aligned}.

\begin{aligned}V &= 2\; \rm dm^{3} \\ &= 2 \; \rm dm^{3} \times \frac{1\; \rm m^{3}}{10^{3}\; \rm dm^{3}} \\ &= 2 \times 10^{-3}\; \rm m^{3}\end{aligned}.

Look up the ideal gas constant in the corresponding units: R \approx 8.31\; \rm m^{3}\cdot Pa \cdot mol^{-1} \cdot K^{-1}.

Let n denote the number of moles of this gas in that V = 2\; \rm dm^{3}. By the ideal gas law, if this gas is an ideal gas, then the following equation would hold:

P \cdot V = n \cdot R \cdot T.

Rearrange this equation and solve for n:

\begin{aligned}n &= \frac{P \cdot V}{R \cdot T} \\ &\approx \frac{1.01325 \times 10^{5}\; {\rm Pa} \times 2 \times 10^{-3}\; {\rm m^{3}}}{8.31 \; {\rm m^{3} \cdot Pa \cdot mol^{-1} \cdot K^{-1}} \times 293.15\; {\rm K}} \\ &\approx 0.08\; \rm mol\end{aligned}.

In other words, there is approximately 2\; \rm mol of this gas in that V = 2\; \rm dm^{3}.

6 0
2 years ago
A solution labeled "0.105 M NaOH" would contain ______________ moles of NaOH in each liter of solution.
dem82 [27]

Answer:

A solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.

Explanation:

The concentration of a solution in Molarity (M) stands for the number of moles of that substance contained in 1 L of solution.

Molarity = Concentration in mol/L = (Number of moles of solute) ÷ (Volume of solution in L)

Molarity = Concentration in mol/L = 0.105 M = 0.105 mol/L

Number of moles of solute = ?

Volume of solution in L = 1 L

0.105 = Number of moles of solute × 1

Number of moles of solute = 0.105 mole

Hence, a solution labeled "0.105 M NaOH" would contain 0.105 moles of NaOH in each liter of solution.

Hope this Helps!!!

7 0
3 years ago
Other questions:
  • How many carbon atoms are contained in 2.8 g of c2h4 ?
    13·2 answers
  • The solubility of acetanilide is 12.8 g in 100 mL of ethanol at 0 ∘C, and 46.4 g in 100 mL of ethanol at 60 ∘C. What is the maxi
    8·1 answer
  • What is the difference between a primitive and body centered unit cell?
    7·1 answer
  • What is a molecular orbital? Question 3 options: Another method of describing the orbitals of individual atoms A mixing of the a
    12·1 answer
  • Which of the following is the most likely sign that a chemical change has happened?
    12·1 answer
  • All chemical reactions use reactants in a specific proportion or stoichiometry to form products. The __________ reactant regulat
    11·2 answers
  • Somebody please help asap​
    5·2 answers
  • Which of the following is true for the equilibrium constant of a reaction?
    14·1 answer
  • What is the mass of an object that creates 33,750J of energy by traveling at<br> 30m/s?
    14·2 answers
  • I need help pleaseee!!!!!!!! Fast
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!