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Irina-Kira [14]
3 years ago
12

What are the signs given to the electrodes in both the voltaic and electrolytic cells? What reaction (oxidation or reduction) is

occurring at each?
Chemistry
1 answer:
Alex3 years ago
4 0
In a voltaic cell, electrons flow from the anode to the cathode. Anode is negative while cathode is positive.

In an electrolytic cell, electron flows from the cathode to the anode. Anode is positive and cathode is negative.

For both, Oxidation occurs at the anode and Reduction occurs at the cathode.
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How many grams of diphosphorus pentoxide result if 100.0 g of phosphorus are combined with sufficient oxygen?
gregori [183]
Answer is: 230 g.
Chemical reaction: P₄ + 5O₂ → 2P₂O₅.
m(P₄) = 100 g.
M(P₄) = 4 · 31 g/mol = 124 g/mol.
n(P₄) = m(P₄) ÷ M(P₄) = 100g ÷ 124g/mol = 0,806 mol.
From reaction: n(P₄) : n(P₂O5) = 1 : 2.
n(P₂O₅) = 1,612 mol.
m(P₂O₅) = 1,612 mol · 142g/mol = 230g.
M - molar mass.
n - amount of substance.
3 0
3 years ago
In what state is the carbon dioxide being used by the researchers and why?
Artyom0805 [142]
Carbon dioxide and what state it doesn’t make no sense
8 0
3 years ago
What is the molarity of a nitric acid solution if 43.13 mL 0.1000 M KOH solution is needed to neutralize 30.00 mL of the acid so
Leno4ka [110]

Answer:

0.144M

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

HNO3 + KOH —> KNO3 + H20

From the equation,

nA = 1

nB = 1

From the question given, we obtained the following:

Ma =?

Va = 30.00mL

Mb = 0.1000M

Vb = 43.13 mL

MaVa / MbVb = nA/nB

Ma x 30 / 0.1 x 43.13 = 1

Cross multiply to express in linear form

Ma x 30 = 0.1 x 43.13

Divide both side by 30

Ma = (0.1 x 43.13) /30 = 0.144M

The molarity of the nitric acid is 0.144M

8 0
3 years ago
20 ML of a gas at 200 K is heated until the new volume is 55ML what is the final temperature of the gas
MrRa [10]

Answer:

T2 = 550K

Explanation:

From Charles law;

V1/T1 = V2/T2

Where;

V1 is initial volume

V2 is final volume

T1 is initial temperature

T2 is final temperature

We are given;

V1 = 20 mL

V2 = 55 mL

T1 = 200 K

Thus from V1/T1 = V2/T2, making T2 the subject;

T2 = (V2 × T1)/V1

T2 = (55 × 200)/20

T2 = 550K

8 0
2 years ago
How does the average speed of air molecules relate to the air temperature?
Varvara68 [4.7K]
<span>Temperature is defined as the rate at which molecules move or vibrate

</span>
8 0
3 years ago
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