Answer:
Distance to the xy-plane = |z|
Distance to the yz-plane = |x|
Distance to the xz-plane = |y|
Step-by-step explanation:
The distance from P(x,y,z) to the xy-plane is by definition the magnitude of the vector that goes from the perpendicular projection of P over the xy-plane to the point P, which is exactly the magnitude of the vector (0,0,z) = |z| the absolute value of z
Similarly, the distance from P to the yz-plane is |x| and the distance from P to the xz-plane is |y|
Distance to the xy-plane = |z|
Distance to the yz-plane = |x|
Distance to the xz-plane = |y|
The length of AD is 75. Since opposite sides have the same length, 63 plus 63 is 126. The perimeter is 276, so 276 minus 126 is 150. 150 divided by 2 is 75.
First make the original multiplier:
1+(6.3/100) = 1.063
Then divide the final number by the original multiplier:
201,000 / 1.063 = 189087
So the answer is d
Hope this helps! :)
Y= 11-2x
Substitute in:
5x-2(11-2x)=-13
5x-22+4x=-13(combine like-terms)
9x-22=-13
9x=-13+22
9x=9
x=1
