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Alik [6]
3 years ago
11

(-3,2), (11,-1) Give the slope between the two points.

Mathematics
2 answers:
Ahat [919]3 years ago
7 0

Answer:

m=-\frac{3}{14}

Step-by-step explanation:

m=\frac{rise}{run}=\frac{-1-2}{11+3}=\frac{-3}{14}  = -\frac{3}{14}

Hope this helps.

ValentinkaMS [17]3 years ago
3 0

Answer:

Look below! Make brainliest as well please!

Step-by-step explanation:

The way to find a slope is with this equation:  (y2-y1)/(x2-x1). So in this case, we do (-1-2)/11-(-3)) and we get (-3)/11+3 which equals (-3)/(14). If you can simplify, make sure to!

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Which expression is equivalent to 6–3?
Bond [772]

Your question is not well presented. See complete question below

Which expression is equivalent to 6^{-3}?

A) –63

B) 36

C) \sqrt[3]{6}

D) (\frac{1}{6} )^3

Answer:

The equivalent of 6^{-3 is (\frac{1}{6} )^3

Step-by-step explanation:

Given

Expression: 6^{-3}

Required:

Find the Equivalent Expression

To find the equivalent of this expression, we make use of law of indices.

One of the laws of indices states that

a^-b = \frac{1}{a^b}

If we apply this law to the expression above (6^{-3})

By comparison a = 6 and b = 3.

So, 6^{-3} becomes

6^{-3} = \frac{1}{6^3}

Simplifying further;

\frac{1}{6^3} = \frac{1}{6 * 6 * 6}

This can also be written as

\frac{1}{6^3} = \frac{1*1*1}{6 * 6 * 6}

By splitting the above expression; we have that

\frac{1}{6^3} = \frac{1}{6} * \frac{1}{6} * \frac{1}{6}

Multiplication law of indices states that;

a * a * a = a³. (Because they have the same base of a)

So, \frac{1}{6} * \frac{1}{6} * \frac{1}{6} can then be written as (\frac{1}{6} )^3

Hence,  \frac{1}{6^3} = (\frac{1}{6} )^3

So, the equivalent of 6^{-3} is (\frac{1}{6} )^3

7 0
3 years ago
Rachel spent $12 for socks. This was $3 more than one-fourth what she spent on shoes. Which equation, when solved for x, gives t
lilavasa [31]

Answer:

B) 4X + 3 = 12

Step-by-step explanation:

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5 0
4 years ago
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Mariulka [41]

Answer:

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Step-by-step explanation:

<u>PART A</u>

Simplify the expression by solving out the square roots.

\frac{\sqrt{16} \sqrt{p} }{\sqrt{p}} = \frac{4 \sqrt{p} }{\sqrt{p}}

You can cancel out the \sqrt{p} on the top and bottom.

So, a should be 4.

<u>PART B</u>

Solve out the square root. The square root is pretty much the 1/2 power, so you can divide the exponents by half.

\frac{\sqrt{y^{10}} }{\sqrt{4y^{5}} } = \frac{y^{5}}{2y^{\frac{5}{2}} }

You can subtract exponents to divide them. So the y variable becomes y^{5 - 5/2}, or y^{5/2}.

Then, the overall expression is \frac{1}{2} y^{\frac{5}{2} }, or you can turn that into \frac{1}{2} \sqrt{y^5}.

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer: 1.50

Step-by-step explanation:

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4 years ago
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