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3 years ago

Please help!!! I'll mark you as BRAINLIEST and give you 10 points!!!!!

Mathematics

1 answer:

zheka24 [161]3 years ago

5 0

Answer:

Step-by-step explanation:

Okay so the shape has an area of 60 square inches. The formula for the area of a triangle is A = b*h where A = area, b = base, and h = height

So we are given the value for A (60)

We are given the value for height (10)

So we just need to find the value of the base

So let's set this up as an equation. Input the given values into the area for triangle formula

A = B*h

60 = B * 10

So we need to solve for B. To do that we need to get B alone on one side of the = sign. B is being multiplied by 10 so do the opposite and divide both sides by 10

60 divided by 10 = 6

10 divided by 10 = 1 (don't actually put a 1 down, just drop it)

So we are left with

6 = B

So the base is 6 square inches. To test, put it in the equation:

A = B*h

60 = 6*10

60 = 60

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Need help on this!!!!

Alexxandr [17]

Answer:

(a) area = 3y^2 +14y +16
(b) perimeter = 8y +20

Step-by-step explanation:

Part of the point of Algebra is that you can work with things that stand for numbers (almost) as easily as working with numbers themselves. Here, you are given values that stand for the length and width of the rectangle.

(a) You know the area of a rectangle is found by multiplying its length by its width. The same is true when length and width are algebraic expressions that stand for those numbers.

Given: length = 3y+8, width = y+2

Find: area = length × width

Solution:

area = (3y+8) × (y+2)

Using the distributive property, we can perform this multiplication in essentially the same way we would for the numbers 38 and 12.

area = 3y(y +2) +8(y +2) equivalent to 30(12) +8(12)

= 3y^2 +6y +8y +16 equivalent to 30·10 +30·2 +8·10 +8·2

area = 3y^2 +14y +16 equivalent to 3·10^2 +14·10 +16

(Of course, with numbers, there are relationships between units and tens and hundreds that let us further combine terms. When variables are involved, we can combine terms with the same power of the variable, but we cannot combine "y" terms with "y^2" terms the way we can with numbers.)

___

(b) The perimeter is the sum of the lengths of the four sides of the rectangle. Since two of those sides are "length" and two are "width", we can write ...

perimeter = 2(length + width)

Making the substitution for length and width as defined above, we have

perimeter = 2((3y+8) + (y+2))

= 2(3y+y + 8+2) = 2(4y +10)

perimeter = 8y +20

5 0

2 years ago

Find the GCF. 18c3 and 24c3

12345 [234]

Answer:

6c³

Step-by-step explanation:

18c³ = 2 × 3 × 3 × c × c × c

24c³ = 2 × 2 × 2 × 3 × c × c × c

Now we show the common factors in bold:

18c³ = 2 × 3 × 3 × c × c × c

24c³ = 2 × 2 × 2 × 3 × c × c × c

The common factor are:

2, 3, c, c, c

GCF = 2 × 3 × c × c × c = 6c³

6 0

3 years ago

helP!!! 20 POINTS PLUS BRAINLIEST!!! An electrician cuts a 20 ft piece of wire into two pieces. One piece is 6ft longer then the

Vlada [557]

13 and 7
Hope this helped

8 0

3 years ago

Read 2 more answers

The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

3 years ago

Read 2 more answers

What is the line of symmetry for the parabola whose equation is y = 3x2 + 24x - 1? x = -8 x = -6 x = -4

Viktor [21]

X= -b/2a = -24/6 = -4

4 0

3 years ago

Read 2 more answers