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zavuch27 [327]
3 years ago
5

determine the length of a chord whose central angle is 75° in the circle with the radius of 12 inches. ​

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

Step-by-step explanation:

other two sides joining center to the ends of chord=radius of circle=12 in

using cosine formula

cos A=\frac{b^2+c^2-a^2}{2bc} \\2bc cos~A=b^2+c^2-a^2\\\angle A=75^\circ\\b=c=r=12~in\\2*12*12~cos~75=12^2+12^2-a^2\\a^2=2*12^2-2*12^2 cos ~75\\a^2=2*12^2(1-cos 75)\\a=12\sqrt{2(1-cos~75)} \approx 14.6~inches

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Step-by-step explanation:

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Given the lengths of the sides which of the following would NOT be a right triangle?
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2 years ago
HELP ME!!!
larisa [96]

Answer:

  -2, 8/3

Step-by-step explanation:

You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...

  A = (1/2)(f(a) +f(4))(4 -a)

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We want this area to be 12, so we can substitute that value for A and solve for "a".

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The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.

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<em>Alternate solution</em>

The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.

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Dmitriy789 [7]

Answer:

See explanation

Step-by-step explanation:

Jane is given a $100 gift to start and saves $35 a month from her allowance.

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