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3 years ago

When x rays are passed through successive aluminium sheets, their hardness ___.

Physics

1 answer:

Sidana [21]3 years ago

4 0

Answer:

decreases

Explanation:

on each collision, the electrons that make up x-rays get absorbed.

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In a head-on collision, a ball of mass 0.3 kg travelling with velocity 2.8 m/s in the positive x-direction hits a stationary sec

Pie

Answer:

The final velocity of the first ball (0.3 kg) is 0.4 m/s in negative x direction.

Explanation:

Given;

mass of the first object, m₁ = 0.3 kg

initial velocity of the first ball, u₁ = 2.8 m/s

mass of the second ball, m₂ = 0.4 kg

initial velocity of the second ball, u₂ = 0

let the final velocity of the first ball, = v₁

let the final velocity of the second ball, = v₂

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(0.3 x 2.8) + (0.4 x 0) = 0.3v₁ + 0.4v₂

0.84 = 0.3v₁ + 0.4v₂

2.8 = v₁ + 1.333v₂ -------equation (1)

Apply one-direction velocity;

u₁ + v₁ = u₂ + v₂

2.8 + v₁ = 0 + v₂

v₂ = 2.8 + v₁

substitute the value of v₂ into equation (1)

2.8 = v₁ + 1.333v₂

2.8 = v₁ + 1.333(2.8 + v₁)

2.8 = v₁ + 3.732 + 1.333v₁

2.8 - 3.732 = v₁ + 1.333v₁

-0.932 = 2.333v₁

v₁ = -0.932 / 2.333

v₁ = -0.4 m/s

Therefore, the final velocity of the first ball (0.3 kg) is 0.4 m/s in negative x direction.

8 0

3 years ago

The purpose of the air filter is to

marishachu [46]

The purpose of an air filter is to purify the air around you removing particles such as dust from the air.

8 0

3 years ago

Read 2 more answers

Three people are pushing a 500 kg of box in the same direction. applied forces are 30 n, 20 n, and 10 n respectively. if the acc

GREYUIT [131]

The total force applied by the three people is:
$F=30 N+20 N+10 N=60 N$
This force is pushing toward the direction of the motion, while the frictional force $F_f$ points in the opposite direction.
We can write Newton's second law applied to the block: the resultant of the two forces must be equal to the product between the block's mass and its acceleration
$F-F_f = ma$
We know the mass of the block, m=500 kg, and the acceleration, $a=0.02 m/s^2$ , so we can find the friction:
$F_f = F-ma=60 N - (500 kg)(0.02 m/s^2)=50 N$

8 0

4 years ago

*photo attached* The diameters of the main rotor and tail rotor of a single-engine helicopter are 7.67 m and 1.01 m, respectivel

stiks02 [169]

(a) The speeds of the tips of both rotors; main rotor <u>178.3 m/s</u> and tail rotor <u>218.4 m/s</u>.

(b) The speed of the main rotor is <u>0.52</u> speed of sound, and the speed of the tail rotor is <u>0.64</u> speed of sound.

<h3>Linear speed of main motor and tail rotor</h3>

v = ωr

where;

ω is the angular speed (rad/s)
r is radius (m)

v(main rotor) = (444 rev/min x 2π rad x 1 min/60s) x (0.5 x 7.67 m)

v(main rotor) = 178.3 m/s

v(tail rotor) = (4,130 rev/min x 2π rad x 1 min/60s) x (0.5 x 1.01 m)

v(tail rotor) = 218.4 m/s

<h3>Speed of the rotors with respect to speed of sound</h3>

% speed (main motor) = 178.3/343 = 0.52 = 52 %

% speed (tail motor) = 218.4/343 = 0.64 = 64 %

Thus, the speed of the main rotor is 0.52 speed of sound, and the speed of the tail rotor is 0.64 speed of sound.

Learn more about linear speed here: brainly.com/question/15154527

#SPJ1

5 0

2 years ago

A 2.00-kg block is pushed against a spring with negligible mass and force constant k = 400 N/m, compressing it 0.220 m. When the

marin [14]

Answer:

0.82052 m

Explanation:

potential energy of spring = kinetic energy

=> 0.5kx^2 = 0.5mv^2

=> $v=\sqrt{\frac{kx^2}{m} }$

$v=\sqrt{\frac{400\times 0.220^2}{2} }$

v= 3.11127 m/s

angle = 37°

thus height = distance×sin(37) = D×0.60182

Also,

m×g×h = 0.5×m×v^2

=> 2×9.8×D×0.60182 = 0.5×2×3.11127×3.11127

=> D = 0.82052 m

4 0

3 years ago