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pantera1 [17]
3 years ago
6

When x rays are passed through successive aluminium sheets, their hardness ___.

Physics
1 answer:
Sidana [21]3 years ago
4 0

Answer:

decreases

Explanation:

on each collision, the electrons that make up x-rays get absorbed.

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Which element contains a full 2p orbital in its valence shell
alex41 [277]
So Neon ( Ne) is the correct answer.

3 0
4 years ago
Read 2 more answers
Why are stars so important to life on Earth?
sveticcg [70]

Answer:

B

Explanation:

The reason why is simple all stars hold key... compounds necessary to life. when a star supernovas it blast all of those out like a shotgun.

7 0
3 years ago
How many electrons must be transferred from an object to produce a charge of 1.15 c? (express your answer to three significant f
Darina [25.2K]
<span>To produce a charge of 1.15 Coulombs in an object, we need to transfer = 1.15/(charge on an electron) number of electrons

   As we know that, total charge on an electron = 1.60217662 Ă— 10 ^-19 coulombs
    Hence, number of electrons required to move = 1.15/(1.60217662 Ă— 10 ^-19) = 0.71777 x 10^19 electrons, i.e. 7.17 x 10^18 electrons upto 3 significant figures</span>
6 0
4 years ago
On planet X, an object weighs 19.7 N. On planet B where the magnitude of the free-fall acceleration is 1.92 g (where g = 9.8 m/s
sergey [27]

Answer:

Mass of object in Earth = 1.58 kg.

Free-fall acceleration on planet X = 12.47 m/s²

Explanation:

We know weight is the product of mass and acceleration due to gravity.

Mass is a constant.

           W = mg

On planet X, an object weighs 19.7 N.

      W_X=mg_X\\\\19.7=mg_X

On planet B where the magnitude of the free-fall acceleration is 1.92 g (where g = 9.8 m/s^2 is the gravitational acceleration on Earth), the object weighs 29.8 N.

           W_B=mg_B\\\\29.8=m\times 1.92\times 9.81\\\\m=1.58kg

Mass of object in Earth = 1.58 kg.

We need to find free-fall acceleration on planet X.

     19.7=mg_X\\\\g_X=\frac{19.7}{1.58}=12.47m/s^2

Free-fall acceleration on planet X = 12.47 m/s²

4 0
3 years ago
A sports event, the car starts from rest, in 5.0 s its acceleration is 5.0 m/s2.
n200080 [17]

Answer:

62.5m

Explanation:

Given parameters:

Time  = 5s

Acceleration  = 5m/s²

Unknown:

Distance traveled by car  = ?

Solution:

To solve this problem, we use one of the motion equations as given below:

     S  = ut + \frac{1}{2} at²

S is the distance traveled

t is the time taken

u is the initial velocity  = 0m/s

a is the acceleration

Now insert the parameters and solve;

      S = (0 x 5) + (\frac{1}{2} x 5 x 5²) = 62.5m

6 0
3 years ago
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