Elastic energy (E1) stored in the spring when it is stretched by x :
<span>=1/2kx^2=1.5J </span>
<span>when it is stretched 3 times more=>x becomes 3x
</span>so
<span>E2=1/2k(3x)^2 </span>
<span>=1/2k{9x^2} </span>
<span>=9{1/2kx^2} </span>
<span>={(E1}</span>
<span>=9{1.5} </span>
<span>=13.5J
hope it helps</span>
Answer:
(a) Force and Pressure
Explanation:
Acc to the formula,
Force = Pressure/Area
Therefore it depends on force and pressure
Answer:
Explanation:
Lets see the given parameters.
Length of wire (L) = 6.93
Linear Density of wire (m/L) = 0.019 kg/m
Tension Force (F) = 365 Newtons
Now, the fundamental frequency () of the wire is given by the formula:
Where
L is length of wire
F is the tension force
m/L is the linear density
Plugging in, we get:
We can say the fundamental frequency to be about 10 Hz
Now, we know that the lowest frequency humans can hear is 20 Hz.
The lowest harmonic number is gotten by dividing this by the fundamental frequency:
20/10 = 2
Thus,
n = 2