Answer:
The angular velocity is <em>35.5 rad/s.</em>
Explanation:
Step 1: Find the moment of Inertia for the rod
The moment of inertia, <em>I</em>, of a rod:
<em>
.......... (1)</em>
where M = mass of rod (0.78 Kg); L = Length of rod (0.54 m).

Step 2: Calculate the angular acceleration from Rotational kinetic notation
<em>F.r = I.α ........... (2)</em>
<em>where F is the force acting upon the rod; r is the half length of the rod; I is the moment of Inertia and; α is the angular acceleration.</em>
<em>∴ (1000 N)(0.27 m) = 0.019α</em>
<em>α = 270 Nm / 0.019 Kgm²</em>
<em>α = 14210.5 rad/s</em>
Step 3: We find the angular velocity by using the equation below:
<em>ωf = ωi + αt ......... (3)</em>
<em>where </em>
<em>ωf is the angular velocity after the blow</em>
<em>ωi is the angular velocity before the blow = 0</em>
<em>t is the time taken for the blow to occur = 2.5 ms</em>
<em>ωf = 0 + (14210.5 rad/s)(2.5 ms) = 35.5 rad/s.</em>
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