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zavuch27 [327]
4 years ago
11

If a kestrel eats a mouse that eats grass the kestrel is a

Physics
2 answers:
vovangra [49]4 years ago
5 0
<span> Second-level consumer </span>
Vinil7 [7]4 years ago
4 0

Second Level Consumer

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An energy resource that can be replaced in a reasonable short period of time is call an
Semenov [28]
A Renewable resource
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4 years ago
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Calculate the momentum of a 2000-kg elephant charging a hunter at a speed of 7.50 m/s . (b) compare the elephant's momentum with
Sergio [31]

(a) The momentum of a moving object is given by:

p=mv

where m is the mass of the object and v is its speed. In this problem, the mass of the elephant is m=2000 kg and its speed is v=7.50 m/s, therefore its momentum is

p=(2000 kg)(7.50 m/s)=15000 kg m/s


(b) We can use the same formula to calculate the momentum of the tranquilizer dart, whose mass is m=0.04 kg and whose speed is v=600 m/s:

p=mv=(0.04 kg)(600 m/s)=24 kg m/s

we see that the elephant's momentum is much larger than the momentum of the dart.


(c) Again, using the same formula, the mass of the hunter is m=90 kg, his speed is v=7.40 m/s, therefore his momentum is

p=mv=(90 kg)(7.40 m/s)=666 kg m/s

6 0
4 years ago
Suppose you take a whole apple pie (because pie is better than cake!!) How do the shape, taste, and the weight of the whole pie
Bas_tet [7]

Answer:

I ATE APPLE PIE YESTERDAY

Explanation:

7 0
3 years ago
The pressure of a gas in a container is 1.85 atm and occupies a volume of 12.5 L. If the original volume is reduced by half at c
elixir [45]

Answer:

3.7 atm i.e., pressure doubles

Explanation:

P₁ = Initial pressure = 1.85 atm

P₂ = Final pressure

V₁ = Initial volume = 12.5 L

V₂ = Final volume = 0.5V₁

T = Temperature is constant

From ideal gas law

P₁V₁ = P₂V₂

\\\Rightarrow P_2=P_1\frac{V_1}{V_2}\\\Rightarrow P_2=1.85\frac{V_1}{0.5V_1}\\\Rightarrow P_2=1.85\frac{1}{0.5}\\\Rightarrow P_2=1.85\times 2\\\Rightarrow P_2=3.7\ atm

∴ Final pressure is 3.7 atm i.e., pressure doubles

4 0
3 years ago
A plank 2.00 cm thick and 13.0 cm wide is firmly attached to the railing of a ship by clamps so that the rest of the board exten
charle [14.2K]

Answer:

9.93 MPa

Explanation:

Given:

 - mass of the man = 68.4 kg

 - Deflection dx = 5.2 cm

 - thickness of plank t = 2.0 cm

 - width of plank w = 13.0 cm

 - Length subtended L = 2.0 m

Find:

Shear Modulus of Elasticity S :

                 S = shear stress / shear strain

                        Shear stress = F / A

                        Shear stress = 68.4*9.81 / 0.02*0.13

                        Shear stress = 258078.4615 Pa

                        Shear strain = dx / L

                        Shear Strain = 0.052 / 2

                        Shear Strain = 0.026  

Hence,

                  S = 258078.4615 / 0.026

                  S = 9.93 MPa

5 0
3 years ago
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