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3 years ago

PLEASE HELP (this is all my points I’ll mark brainlist anything please help)

Mathematics

2 answers:

timurjin [86]3 years ago

5 0

Answer:

I believe that it would be A+C+S but is there more to the question?

Step-by-step explanation:

hram777 [196]3 years ago

5 0

omg

Step-by-step explanation:

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Plz answer my question -(4b-6b-7b)

GalinKa [24]

Step-by-step explanation:

-(4b-6b-7b)

= -4b+6b+7b

=9b

8 0

3 years ago

An $80 dress is marked down 25%. Find the price of the dress after the discount

Flura [38]

$80 times 0.25 equals 20
80 minus 20 equals 60 bucks

8 0

3 years ago

A classmate simplified a rational expression below

lara31 [8.8K]

<h2>Part a) </h2><h2>Explain the error in this simplification.</h2>

Given the simplified expression

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

$\:1-2x-4=x^2-x-2$

$-2x-3=x^2-x-2\:\:$

$0=x^2-2x-2\:\:$

$0=\left(x-1\right)\left(x-1\right)$

$x=1$

<u><em>Identifying the Main Error</em></u>

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$ ← ERROR Starts here

<u><em>Here is the Explanation of the Error </em></u>

<u><em /></u> $\mathrm{The\:equation\:should\:have\:been\:Multiplied\:by\:LCM=}\left(x-2\right)\left(x+2\right)$ <em>. </em>In your case you wrongly multiply the equation.

<em><u>CORRECTION</u></em>

<em>HERE IS HOW YOU SHOULD HAVE MULTIPLIED BY </em><em>LCM = (x-2)(x+2):</em>

<em />

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)$

$\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

<h2>Part b) </h2><h2>Show your work as you correct the error</h2>

Here is the complete correction of the error.

Considering the expression

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}x-2,\:x+2:\quad \left(x-2\right)\left(x+2\right)$

$1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)$

$\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

$x^2-2x-8=x^2-x-2$

$x^2-2x-8+8=x^2-x-2+8$

$x^2-2x=x^2-x+6$

$-x=6$

$\frac{-x}{-1}=\frac{6}{-1}$

$x=-6$

3 0

3 years ago

Help its math ik u like math

choli [55]

Answer:

141.625

Step-by-step explanation:

$\: \: 141.625\\ 32 \sqrt{4532} \\ - 32 \\ - - - - - \\ \: \: \: \: 133 \\ - 128 \\ - - - - - - \\ \: \: \: \: \: \: \: \: \: \: 52 \\ \: \: \: \: \: \: - 32 \\ - - - - - - \\ \: \: \: \: \: \: \: \: \: 200 \\ \: \: \: \: \: - 192 \\ - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: 80 \\ \: \: \: \: \: \: \: \: - 64 \\ - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 160 \\ \: \: \: \: \: \: \: \: \: \: \: \: - 160 \\ - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: 0$

7 0

3 years ago

Read 2 more answers

Find the area of the circle and explain how u got the answer . thanks

trasher [3.6K]

A = (pi)r^2

diameter = 12 in

radius = d/2 = 6 in

A = (pi)6^2

A = 36(pi)

3 0

3 years ago