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alina1380 [7]
3 years ago
14

14.3-352-2 i need helppppp

Mathematics
2 answers:
Makovka662 [10]3 years ago
7 0

Answer:

-339.7

Step-by-step explanation:

quickmaths

inessss [21]3 years ago
3 0

Answer: 335.7

Step-by-step explanation:

If the problem is

14.3

-352

2

———

335.7

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A factory made 357,945 baseball bats over the last 2 years. During that time, the factory made 490,867 little league baseballs a
mojhsa [17]

Answer:

522,761 baseballs

Step-by-step explanation:

Number of baseball bats produced over the last 2 years = 357, 945

Number of little league baseballs produced over the last 2 years = 490,867

Number of major league baseballs produced over the last 2 years = 389,839

Total number of baseballs produced over the period = 490,867 + 389,839

                                                                                         = 880,706

Number of baseballs manufactured more than bats = 880,706 - 357945

                                                                                      = 522,761

There are 522,761 baseballs produced more than bats during the 2 years.

8 0
3 years ago
​Mary Cardenas had a policy with a $500 deductible, which paid 80% of her covered charges less deductible. She had medical expen
kipiarov [429]
Ok so let me help you in here:
<span>After she pays $500 toward her medical expenses for the year, her insurance will pay 80% of the $12,500 cost. So
12,500 x .80 = 10,000. Then 12,500-10,000 = $2,500.
So you pay $2500 and the insurance company pays $10,000.
</span>Hope this is useful
8 0
3 years ago
Read 2 more answers
Solve for x and y please
mr_godi [17]

Answer:

try photo math the app

Step-by-step explanation:

it will show you a step to step work out

3 0
3 years ago
Find the deriative dy/dx for y=x^2-2x/x^3+3
vaieri [72.5K]

Answer:

\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})

Step-by-step explanation:

So we want to find the derivative of the rational equation:

y=\frac{x^2-2x}{x^3+3}

First, recall the quotient rule:

(\frac{f}{g})'=\frac{f'g-fg'}{g^2}

Let f be x^2-2x and let g be x^3+3.

Calculate the derivatives of each:

f=x^2-2x\\f'=2x-2

g=x^3+3\\g=3x^2

So:

\frac{dy}{dx}=(\frac{x^2-2x}{x^3+3})'

Use the above format:

\frac{dy}{dx}=\frac{f'g-fg'}{g^2}\\\frac{dy}{dx}=(\frac{(2x-2)(x^3+3)-(x^2-2x)(3x^2)}{(x^3+3)^2})

And that's our answer :)

(If you want to, you can also expand. However, no terms will be canceled.)

8 0
3 years ago
(-3d+4)–(6d–9)<br> (add and subtract linear expressions)
Vlada [557]

Answer:

−9d+13

Step-by-step explanation:

3d+4−(6d−9)

Distribute the Negative Sign:

=−3d+4+−1(6d−9)

=−3d+4+−1(6d)+(−1)(−9)

=−3d+4+−6d+9

Combine Like Terms:

=−3d+4+−6d+9

=(−3d+−6d)+(4+9)

=−9d+13

Answer:

=−9d+13

6 0
2 years ago
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