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hjlf
3 years ago
6

A rock with a mass of 70 grams is dropped into a graduated cylinder with 30 mL of water in it. The water level rose to 35 mL cal

culate the density of the rock in g/mL
Chemistry
2 answers:
Scilla [17]3 years ago
5 0

Answer:

14

Explanation:

70g/(35mL-30mL)=14g/mL

Andrews [41]3 years ago
5 0

Answer:

14 g/mL

Explanation:

The formula to find the density is p=m/v.

The mass is 70 grams. The volume is 5 due the the fact that we subtracted the final volume to the initial volume. Then we divide 70 by 5 and you'll get 14 as your answer.

I hope this helps in the future! Have a great day.

Equation is set below:

p= m/v

p=70/5

p= 14

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3 years ago
How many atoms and ions does lithium sulfite have?
Serhud [2]

Answer:

Hence the<u> ions per mole</u> are:

Li^{+}= 2 ions

SO_{3}^{2-}(aq)= 1 ions

In one mole of Li2SO3 , the number of the atoms are

N_{a}=6.022\times 10^{23}

Explanation:

The formula of  lithium sulfite is Li2SO3.

Li_{2}SO_{3}

It contain Li+ and SO3(2-) ions.This can be represented by :

Li_{2}SO_{3}(s)\rightarrow 2Li^{+}(aq) +SO_{3}^{2-}(aq)

Hence one mole of Li2SO3 will give 2 Li+ ions and 1 SO3 (2-) ion.

Hence the<u> ions per mole</u> are:

Li^{+}= 2 ions

SO_{3}^{2-}(aq)= 1 ions

Number of atoms in  lithium sulfite depends upon the<u> mass of the Li2SO3 present</u> .

Li2SO3 = 93.94 g/mole

This mass is equal to 1 mole of Li2SO3

Now<u> 1 mole</u> of any substance contain Na atoms . This is known as Avogadro Number.

N_{a}=6.022\times 10^{23}

Hence , if 1 mole of Li2SO3 is present then it contains Na atoms

If other then 1 mole present then number of atoms are calculated by:

Number\ of\ Atoms=Moles\times (N_{a})

Here n = number of moles

if the mass of the compound is given then first calculate the number of moles.

Moles=\frac{mass}{Molar\ mass}

6 0
3 years ago
An aqueous salt solution is 15.0% mass sodium chloride. How many grams of salt are in 250.0 grams of this solution? Use correct
Shtirlitz [24]

Answer:

37.5 g NaCl

Explanation:

Step 1: Given data

  • Concentration of NaCl: 15.0% m/m
  • Mass of the solution: 250.0 g

Step 2: Calculate how many grams of NaCl are in 250.0 g of solution

The concentration of NaCl is 15.0% by mass, that is, there are 15.0 g of NaCl every 100 g of solution.

250.0 g Solution × 15.0 g NaCl/100 g Solution = 37.5 g NaCl

5 0
3 years ago
The rate constant for a certain reaction is k = 5.40×10−3 s−1 . If the initial reactant concentration was 0.100 M, what will the
IceJOKER [234]

Answer : The concentration after 17.0 minutes will be, 4.05\times 10^{-4}M

Explanation :

The expression for first order reaction is:

[C_t]=[C_o]e^{-kt}

where,

[C_t] = concentration at time 't'  (final) = ?

[C_o] = concentration at time '0' (initial) = 0.100 M

k = rate constant = 5.40\times 10^{-3}s^{-1}

t = time = 17.0 min = 1020 s (1 min = 60 s)

Now put all the given values in the above expression, we get:

[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}

[C_t]=4.05\times 10^{-4}M

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4 0
3 years ago
How many moles of CaO will be produced from 23.9 g of Ca?<br>2Ca(s) + O2(g) – 20:0(3)<br>mol​
inessss [21]

Answer:

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Explanation:

Given data:

Mass of calcium = 23.9 g

Moles of CaO produced = ?

Solution:

Chemical equation:

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Number of moles = mass/ molar mass

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Now we will compare the moles of calcium and CaO.

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              2          :          2

            0.6         :        0.6

 0.6 moles of CaO will produced.

4 0
3 years ago
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