I would i have think it is either a) east or c) west b/c couldn’t go by it self
Answer:
Hence the<u> ions per mole</u> are:


In one mole of Li2SO3 , the number of the atoms are

Explanation:
The formula of lithium sulfite is Li2SO3.

It contain Li+ and SO3(2-) ions.This can be represented by :

Hence one mole of Li2SO3 will give 2 Li+ ions and 1 SO3 (2-) ion.
Hence the<u> ions per mole</u> are:


Number of atoms in lithium sulfite depends upon the<u> mass of the Li2SO3 present</u> .
Li2SO3 = 93.94 g/mole
This mass is equal to 1 mole of Li2SO3
Now<u> 1 mole</u> of any substance contain Na atoms . This is known as Avogadro Number.

Hence , if 1 mole of Li2SO3 is present then it contains Na atoms
If other then 1 mole present then number of atoms are calculated by:

Here n = number of moles
if the mass of the compound is given then first calculate the number of moles.
Answer:
37.5 g NaCl
Explanation:
Step 1: Given data
- Concentration of NaCl: 15.0% m/m
- Mass of the solution: 250.0 g
Step 2: Calculate how many grams of NaCl are in 250.0 g of solution
The concentration of NaCl is 15.0% by mass, that is, there are 15.0 g of NaCl every 100 g of solution.
250.0 g Solution × 15.0 g NaCl/100 g Solution = 37.5 g NaCl
Answer : The concentration after 17.0 minutes will be, 
Explanation :
The expression for first order reaction is:
![[C_t]=[C_o]e^{-kt}](https://tex.z-dn.net/?f=%5BC_t%5D%3D%5BC_o%5De%5E%7B-kt%7D)
where,
= concentration at time 't' (final) = ?
= concentration at time '0' (initial) = 0.100 M
k = rate constant = 
t = time = 17.0 min = 1020 s (1 min = 60 s)
Now put all the given values in the above expression, we get:
![[C_t]=(0.100)\times e^{-(5.40\times 10^{-3})\times (1020)}](https://tex.z-dn.net/?f=%5BC_t%5D%3D%280.100%29%5Ctimes%20e%5E%7B-%285.40%5Ctimes%2010%5E%7B-3%7D%29%5Ctimes%20%281020%29%7D)
![[C_t]=4.05\times 10^{-4}M](https://tex.z-dn.net/?f=%5BC_t%5D%3D4.05%5Ctimes%2010%5E%7B-4%7DM)
Thus, the concentration after 17.0 minutes will be, 
Answer:
0.6 moles of CaO will produced.
Explanation:
Given data:
Mass of calcium = 23.9 g
Moles of CaO produced = ?
Solution:
Chemical equation:
2Ca + O₂ → 2CaO
Number of moles of calcium:
Number of moles = mass/ molar mass
Number of moles = 23.9 g / 40 g/mol
Number of moles = 0.6 mol
Now we will compare the moles of calcium and CaO.
Ca : CaO
2 : 2
0.6 : 0.6
0.6 moles of CaO will produced.