Answer:
Mass of SO₂ can be made from 25.0 g of Na₂SO₃ and 22 g of HCl = 12.672 g
Explanation:
SO₂( sulfur dioxide) can be produced in the lab. by the reaction of hydrochloric acid & sulphite salt such as sodium.
the balanced chemical equation is as follows
Na₂SO₃ + 2 HCl → 2 NaCl + SO₂ + H₂O
Moles of Na₂SO₃ = ![\frac{Mass}{Molecular mass} =\frac{25}{126} = 0.198](https://tex.z-dn.net/?f=%5Cfrac%7BMass%7D%7BMolecular%20mass%7D%20%3D%5Cfrac%7B25%7D%7B126%7D%20%3D%200.198)
Moles of HCl = ![\frac{mass}{molecular mass}=\frac{22}{36.5}= 0.6](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bmolecular%20mass%7D%3D%5Cfrac%7B22%7D%7B36.5%7D%3D%200.6)
using mole ratio method to find limiting reagent
For sodium sulfite ![\frac{mole}{stoichiometry} = \frac{0.198}{1}= 0.198](https://tex.z-dn.net/?f=%5Cfrac%7Bmole%7D%7Bstoichiometry%7D%20%20%3D%20%5Cfrac%7B0.198%7D%7B1%7D%3D%200.198)
for HCl ![\frac{mole}{stoichiometry} = \frac{0.6}{2}= 0.3](https://tex.z-dn.net/?f=%5Cfrac%7Bmole%7D%7Bstoichiometry%7D%20%20%3D%20%5Cfrac%7B0.6%7D%7B2%7D%3D%200.3)
since <u>sodium sulfite</u> is <u>limiting reactant</u> for above chemical reaction
1 mole of Na₂SO₃ produce 1 mole of SO₂
0.198 mole of Na₂SO₃ produce 0.198 mole of SO₂
∴ Mass of SO₂ produce = mole x molar mass of SO₂
= 0.198 x 64
= 12.672 g
Answer:
FeSO2
Explanation:
Please see attached picture for full solution.
Height of wave - amplitude
Higher the pitch - higher the frequency
Louder - higher the amplitude
bottom of the wave - trough
distance from crest to crest - wave length
top of the wave - crest
To be able to write correctly the equilibrium expression of a reaction, we need to know the balanced reaction and the phases of the substances in the reaction. When substances are solid, pure liquid they are not included in the expression. We do as follows:
<span>4KO2(s) + 2H2O(g) = 4KOH(s) + 3O2(g)
K = [O2]^3 / [H2O]^2</span>
Answer: it would be b time taken by the glass surface to dry
Explanation:
i had took the test and i got it right