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3 years ago

Lots of points!!! Will give brainliest!

Mathematics

1 answer:

alekssr [168]3 years ago

8 0

The second equation is already solved for y, so we substitute it into the first equation.

x + 6y = 6

x + 6(1/3 x - 2) = 6

x + 2x - 12 = 6

3x = 18

x = 6

Now substitute 6 for x in the second original equation and solve for y.

y = 1/3 x - 2

y = 1/3 * 6 - 2

y = 2 - 2

y = 0

Answer: x = 6 and y = 0

You might be interested in

Kate bought a T-shirt for $12.95 and a pair of shorts for $10.95. She paid 6.25% in tax. What is her total amount that she paid?

sergeinik [125]

Kate paid $25.39 for her purchases.

Kate will receive $24.61 in change.

Step-by-step explanation:

Given,

Cost of t-shirt = $12.95

Cost of pair of shorts = $10.95

Total = cost of t-shirt + cost of pair of shorts

Total = 12.95 + 10.95 = $23.90

Sales tax = 6.25% of total amount

Amount of sales tax = $\frac{6.25}{100}*23.90=\frac{149.375}{100}$

Amount of sales tax= $1.49

Total amount with sales tax = 23.90 + 1.49 = $25.39

Kate paid $25.39 for her purchases.

Amount paid = $50

Change received = Amount paid - Bill amount

Change received = 50 - 25.39 = $24.61

Kate will receive $24.61 in change.

Keywords: sales tax, addition

Learn more about addition at:

#LearnwithBrainly

3 0

2 years ago

Square root of 2tanxcosx-tanx=0

kobusy [5.1K]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3242555

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Solve the trigonometric equation:

$\mathsf{\sqrt{2\,tan\,x\,cos\,x}-tan\,x=0}\\\\ \mathsf{\sqrt{2\cdot \dfrac{sin\,x}{cos\,x}\cdot cos\,x}-tan\,x=0}\\\\\\ \mathsf{\sqrt{2\cdot sin\,x}=tan\,x\qquad\quad(i)}$

Restriction for the solution:

$\left\{ \begin{array}{l} \mathsf{sin\,x\ge 0}\\\\ \mathsf{tan\,x\ge 0} \end{array} \right.$

Square both sides of (i):

$\mathsf{(\sqrt{2\cdot sin\,x})^2=(tan\,x)^2}\\\\ \mathsf{2\cdot sin\,x=tan^2\,x}\\\\ \mathsf{2\cdot sin\,x-tan^2\,x=0}\\\\ \mathsf{\dfrac{2\cdot sin\,x\cdot cos^2\,x}{cos^2\,x}-\dfrac{sin^2\,x}{cos^2\,x}=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left(2\,cos^2\,x-sin\,x \right )=0\qquad\quad but~~cos^2 x=1-sin^2 x}$

$\mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\cdot (1-sin^2\,x)-sin\,x \right]=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2-2\,sin^2\,x-sin\,x \right]=0}\\\\\\ \mathsf{-\,\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}\\\\\\ \mathsf{sin\,x\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}$

Let

$\mathsf{sin\,x=t\qquad (0\le t$

So the equation becomes

$\mathsf{t\cdot (2t^2+t-2)=0\qquad\quad (ii)}\\\\ \begin{array}{rcl} \mathsf{t=0}&\textsf{ or }&\mathsf{2t^2+t-2=0} \end{array}$

Solving the quadratic equation:

$\mathsf{2t^2+t-2=0}\quad\longrightarrow\quad\left\{ \begin{array}{l} \mathsf{a=2}\\ \mathsf{b=1}\\ \mathsf{c=-2} \end{array} \right.$

$\mathsf{\Delta=b^2-4ac}\\\\ \mathsf{\Delta=1^2-4\cdot 2\cdot (-2)}\\\\ \mathsf{\Delta=1+16}\\\\ \mathsf{\Delta=17}$

$\mathsf{t=\dfrac{-b\pm\sqrt{\Delta}}{2a}}\\\\\\ \mathsf{t=\dfrac{-1\pm\sqrt{17}}{2\cdot 2}}\\\\\\ \mathsf{t=\dfrac{-1\pm\sqrt{17}}{4}}\\\\\\ \begin{array}{rcl} \mathsf{t=\dfrac{-1+\sqrt{17}}{4}}&\textsf{ or }&\mathsf{t=\dfrac{-1-\sqrt{17}}{4}} \end{array}$

You can discard the negative value for t. So the solution for (ii) is

$\begin{array}{rcl} \mathsf{t=0}&\textsf{ or }&\mathsf{t=\dfrac{\sqrt{17}-1}{4}} \end{array}$

Substitute back for t = sin x. Remember the restriction for x:

$\begin{array}{rcl} \mathsf{sin\,x=0}&\textsf{ or }&\mathsf{sin\,x=\dfrac{\sqrt{17}-1}{4}}\\\\ \mathsf{x=0+k\cdot 180^\circ}&\textsf{ or }&\mathsf{x=arcsin\bigg(\dfrac{\sqrt{17}-1}{4}\bigg)+k\cdot 360^\circ}\\\\\\ \mathsf{x=k\cdot 180^\circ}&\textsf{ or }&\mathsf{x=51.33^\circ +k\cdot 360^\circ}\quad\longleftarrow\quad\textsf{solution.} \end{array}$

where k is an integer.

I hope this helps. =)

3 0

3 years ago

The ratio of pencils to pens in the drawer is 8:14. If there are actually twice as many pencils as in the ratio, how many pencil

dusya [7]

Yo sup??

let the number of pencils and pens be 8x and 14x

x=2

therefore the number of pens and pencils are

16 pencils and 28 pens

Hope this helps

6 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

OLga [1]

y^2(y^2+6) + 6(y^2+6)

(y^2+6)^2

4 0

3 years ago

Solve r=s/17−t for t

mamaluj [8]

T=-r+s/17

Explanation:

6 0

2 years ago