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vova2212 [387]
3 years ago
13

Lots of points!!! Will give brainliest!

Mathematics
1 answer:
alekssr [168]3 years ago
8 0

The second equation is already solved for y, so we substitute it into the first equation.


x + 6y = 6


x + 6(1/3 x - 2) = 6


x + 2x - 12 = 6


3x = 18


x = 6


Now substitute 6 for x in the second original equation and solve for y.


y = 1/3 x - 2


y = 1/3 * 6 - 2


y = 2 - 2


y = 0


Answer: x = 6 and y = 0

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Triangle JKL was translated 12 units vertically and then reflected over the y-axis to create triangle J'K'L' What is the value o
vova2212 [387]

Answer:

B. 6

Step-by-step explanation:

The picture of the question in the attached figure

we know that

A translation and a reflection are rigid transformations, that produce congruent figures'

Remember that

Two figures are congruent if their corresponding sides and their corresponding angles are congruent

In this problem

Triangle JKL and Triangle J'K'L' are congruent

so

JL=J'L'

substitute the given values

8=2x-4

solve for x

2x=8+4\\2x=12\\x=6

5 0
3 years ago
4. The binomial 12x+15 is equivalent to
shepuryov [24]
Answer is (4) 3(4x+5)
7 0
3 years ago
if the ratio of the areas of 2 similar polygons is 32:50, what is the ration of the corresponding side lengths?
Lera25 [3.4K]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\

\bf \cfrac{small}{large}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}\implies \cfrac{s}{s}=\cfrac{\sqrt{32}}{\sqrt{50}}\implies \cfrac{s}{s}=\cfrac{\sqrt{16\cdot 2}}{\sqrt{25\cdot 2}}
\\\\\\
\cfrac{s}{s}=\cfrac{\sqrt{4^2\cdot 2}}{\sqrt{5^2\cdot 2}}\implies \cfrac{s}{s}=\cfrac{4\sqrt{2}}{5\sqrt{2}}\implies \cfrac{s}{s}=\cfrac{4}{5}
6 0
3 years ago
PLEASE HELP ME SOON pleaseeeeeee
algol13

Answer: An equation is a mathematical statement that shows the equal value of two expressions while an inequality is a mathematical statement that shows that an expression is lesser than or more than the other. An equation shows the equality of two variables while an inequality shows the inequality of two variables.

Step-by-step explanation: Hope this helps! :D

5 0
3 years ago
Read 2 more answers
Simplify the following 7 times the square root of 54 - 2 times the square root of 24
EleoNora [17]
The first step for solving this problem is to simplify the radical
7\sqrt{54 - 2} x 2√6
Calculate the product
14\sqrt{(54 - 2) X 6}
Subtract the numbers
14\sqrt{56 x 6}
Simplify the radical
14 x 2\sqrt{13 x 6}
Multiply the numbers
14 x 2√78
Finally,, calculate the product for your final answer
28√78
Let me know if you have any further questions
:)
4 0
4 years ago
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