You are performing an experiment to measure the speed of a car over time. The results are shown in the graph below.

Una partícula alfa, el núcleo de un átomo de helio, tiene una masa de 6.64*10^(-27) kg y una carga de +2e, ¿Qué magnitud y direc

Olegator [25]

Answer:

Remember that the nucleus of an athom is neutral, which means protons, neutrons and electrons have the same and opposite charge so that the net electircal field is zero. In that case, we say the nucleus is estable.

Now, to mantain the equilibrium of the given element, we need an electrical field equal in magintude +2e with opposite direction, that will balance it.

4 0

3 years ago

What is the kinetic energy f a 25kg object movingat a velocity of 10m/s?

alex41 [277]

Using K.E=1/2MV^2
answer is 125joules

5 0

4 years ago

someone help pls. Two students, Mia and Peter, leave school to meet at the local coffee shop. Peter decides to jog to the coffee

cluponka [151]

Answer:

1) The distance further it takes Peter to arrive at the Coffee shop than Mia is 1.24 km

2) Mia's average speed is 6.00 km/hour

Peter's average speed is 8.48 km/hour

4) Mia's average velocity = Peter's average velocity = 6.00 km/hour

Explanation:

The given information from the diagram are;

The distance Peter jogs from school to the flower shop = 2.00 km

The distance Peter jogs from the Flower shop to the Coffee shop = 2.24 km.

The distance Mia walks from school directly to the Coffee shop = 3.00 km

The time it takes both Peter and Mia to arrive at the coffee shop = 30 minutes = 0.5 hour

1) The total distance Peter travels from school to the Coffee shop = 2.00 km + 2.24 km = 4.24 km

The distance Mia travels from school to the Coffee shop = 3.00 km

The distance further it takes Peter to arrive at the Coffee shop than Mia = 4.24 km - 3.00 km = 1.24 km

The distance further it takes Peter to arrive at the Coffee shop than Mia = 1.24 km

2) $Average \ speed = \dfrac{Total \ distance \ traveled}{Total \ time \ taken \ in \ the \ journey}$

$Therefore, \ Mia's \ average \ speed = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour$

Mia's average speed = 6.00 km/hour

$Peter's \ average \ speed = \dfrac{4.24 \ km}{0.5 \ hour}= 8.48 \ km/hour$

Peter's average speed = 8.48 km/hour

4) $Average \ velocicty = \dfrac{Displacement }{Time \ taken}$

The displacement from the School to the Coffee shop is 3.00 km for both Mia and Peter

The time it takes both Peter and Mia to arrive at the Coffee shop from the school is 30 minutes = 0.5 hour

$Therefore, \ Mia's \ average \ velocity = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour$

Mia's average velocity = 6.00 km/hour

$Peter's \ average \ velocity = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour$

Therefore, Peter's average velocity is also = 6.00 km/hour

6 0

3 years ago

PLS HELP FOR PHYSICS PLS

Mumz [18]

Answer:

Chinese app which is number

Explanation:

7 0

3 years ago

When a force is applied to an object, no work is being preformed on the object unless the object____.

Temka [501]

No work is being performed on the object unless the object is moving, as work done = force x distance

8 0

3 years ago