All categories

3 years ago

Practice Activity:

Physics

2 answers:

Serjik [45]3 years ago

8 0

Answer:

where is the question so that i can do my best ???

Explanation:

Otrada [13]3 years ago

4 0

Answer:

What are we are trying to answer?

Explanation:

You might be interested in

A small ball is hung by a string from the ceiling of a train car, so that the ball hangs vertically. Moving from rest, the train

kondor19780726 [428]

Answer:

Explanation:

5 0

4 years ago

Jordan wants to know the difference between using a 60-W and 100-W lightbulb in her lamp. She calculates the energy it would tak

Andreas93 [3]

Answer:

The difference in the amount of energy transferred by the two bulbs is 1200 J.

Explanation:

The energy transferred by the two lightbulbs can be calculated with the given equation:

$E = P*t$

Where P is the power and t is the time

For the 60 W lightbulb:

$E_{60} = P*t = 60 W*30 s = 1800 J$

For the 100 W lightbulb:

$E_{100} = P*t = 100 W*30 s = 3000 J$

Hence, the difference in the amount of energy transferred is:

$E_{t} = E_{100} - E_{60} = 3000 J - 1800 J = 1200 J$

Therefore, the difference in the amount of energy transferred by the two bulbs is 1200 J.

I hope it helps you!

4 0

3 years ago

12- Calculate the power when a force of 60N moves an object over a distance of 0.6 km in 20

alexandr1967 [171]

Hi there!

To solve, we must begin by calculating the total WORK done on the object.

W = F · d (Force · displacement)

Plug in the given values. Remember to convert km to m:

1 km = 1000 m

0.6 km = 600 m

W = 60 · 600 = 36000 J

Now, we can solve for power:

P = W/t

Convert minutes to seconds:

1 min = 60 sec

20 min = 1200 sec

P = 36000/1200 = 30 W ⇒ Choice D.

3 0

3 years ago

Un móvil, que sale desde un punto situado 3 metros a la izquierda del origen y lleva un movimiento uniforme, se sitúa a 12 metro

Verdich [7]

Answer:

x₁ = 15 m, x₂ = 12 m , x_total = 27m, v₁ = 5 m / s , v₂ = - 3 m / s

Explanation:

In this exercise we will use the kinematics of uniform motion

v = d / t

let's apply this equation for the first move

v₁ = Δx / t = (x₂-x₀) / t

v₁ = (12- (-3)) / 3

v₁ = 5 m / s

the distance traveled is x₁ = 15 m

Now let's analyze the return movement

v₂ = Δx / dt

v₂ = (0 - 12) / 4

v₂ = - 3 m / s

The negative sign indicates that the vehicle is moving to the left

the distance traveled is x₂ = 12 m

The total dystonia is

x_total = x₁ + x₂

x_total = 15 +12

x_total = 27m

In the attached we have the graphics of the movement

8 0

4 years ago

A spaceship from a friendly, extragalactic planet flies toward Earth at 0.201 times the speed of light and shines a powerful las

bagirrra123 [75]

Answer:

The wavelength of observed light on earth is 568.5 nm

Explanation:

Given that,

Velocity of spaceship $v= 0.201c$

Wavelength of laser $\lambda= 697\ nm$

We need to calculate the wavelength of observed light on earth

Using formula of wavelength

$\lambda_{0}=\lambda_{e}\times\sqrt{\dfrac{1-\dfrac{v}{c}}{1+\dfrac{v}{c}}}$

$\lambda_{0}=697\times10^{-9}\times\sqrt{\dfrac{1-\dfrac{0.201 c}{c}}{1+\dfrac{0.201c}{c}}}$

$\lambda_{0}=697\times10^{-9}\times\sqrt{\dfrac{1-0.201}{1+0.201}}$

$\lambda=5.685\times10^{-7}\ m$

$\lambda=568.5\times10^{-9}\ m$

$\lambda=568.5\ nm$

Hence, The wavelength of observed light on earth is 568.5 nm

8 0

4 years ago