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3 years ago

What happens when the difference in charge between a cloud and the ground is too great?

Physics

2 answers:

Verdich [7]3 years ago

8 0

Lightning hits the ground

steposvetlana [31]3 years ago

6 0

Lightning strikes the ground

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A ball of radius r rolls on the inside of a track of radius R. If the ball starts from rest at the vertical edge of the track, f

meriva

Answer:

$v=\sqrt{\dfrac{10g(R-r)}{7}}$

Explanation:

Given that

Radius of track = R

Radius of ball = r

The ball can be treated as solid sphere, so

The moment of inertia of ball

$I=\dfrac{2}{5}mr^2$

When the ball reach at the lowest position then it will have both angular and linear speed.

Condition for rolling without slipping v= ωr

Form energy conservation

$mgR=mgr+\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2$

v= ωr

$I=\dfrac{2}{5}mr^2$

$mgR=mgr+\dfrac{1}{2}mv^2+\dfrac{1}{2}\times \dfrac{2}{5}mr^2\omega^2$

$mg(R-r)=\dfrac{1}{2}mv^2+\dfrac{1}{2}\times \dfrac{2}{5}mv^2$

$2mg(R-r)=mv^2+\dfrac{2}{5}mv^2$

$2g(R-r)=\dfrac{7}{5}v^2$

$v=\sqrt{\dfrac{10g(R-r)}{7}}$

3 0

3 years ago

What is population density?

Tpy6a [65]

Population density (in agriculture: standing stock and standing crop) is a measurement of population per unit area or unit volume; it is a quantity of type number density. It is frequently applied to living organisms, and most of the time to humans.

3 0

3 years ago

Read 2 more answers

What is the density of a block of marble that

EleoNora [17]

Explanation:

Solution,

Volume (v)=287 cm^3

Mass(m)=816 g

Density(d)=m/v

=816/287

=2.84

So, the density of the block of marbles is 2.84 g/cm^3.

I hope it helped U

stay safe stay happy

5 0

3 years ago

The Mariana Trench is best known for its

Pachacha [2.7K]

The answer is A) depth.

7 0

3 years ago

Read 2 more answers

a ball (mas .40) is initially moving to the left at 30m/s. After hitting the wall, the ball is moving to the right at 20 m/s. Wh

Step2247 [10]

Answer:

The impulse is -20kg m/s.

Explanation:

given mass of ball = 0.4 kg

The ball is moving towards left with the initial velocity = 30m/s

The momentum in left direction P1 = mv1

= (0.4)(30)

= 12 kg m/s

The given velocity towards right = -20 m/s ( negative sign shows inverse direction)

Momentum towards right, P2 = mv2

P2 = (0.4)(-20)

P2 = -8 kg m/s

The Impulse = change in momentum

= P2 –P1

= -8-12

= -20 kg m/s

6 0

4 years ago