How do we compare stars in different stages of life
2 answers:
You might be interested in
The rate law equation for Ozone reaction
r=k[O][O₂]
<h3>Further explanation</h3>Given
Reaction of Ozone :.
O(g) + O2(g) → O3(g)
Required
the rate law equation
Solution
The rate law is a chemical equation that shows the relationship between reaction rate and the concentration / pressure of the reactants
For reaction
aA + bB ⇒ C + D
The rate law can be formulated:
where
r = reaction rate, M / s
k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹
a = reaction order to A
b = reaction order to B
[A] = [B] = concentration of substances
So for Ozone reaction, the rate law (first orde for both O and O₂) :
Answer: The initial partial pressures of and
is 139.4 torr.
Explanation:
The equilibrium reaction is
initially conc. p p 0
At eqm. p-2x p-x 2x
Given:
The expression for equilibrium constant is :
= 2x =115 torr
= (p-2x) = p-115 torr
= (p-x)= p-57.5 torr
Now put all the given values in this expression, we get
Therefore, the initial partial pressures of and
is 139.4 torr.