<span>Sodium carbonate (Na2CO3) reacts with acetic acid (CH3COOH) to form sodium acetate (NaCH3COO), carbon dioxide (CO2), and water (H2O). A chemist carries out this reaction in a bomb calorimeter. The reaction causes the temperature of a bomb calorimeter to decrease by 0.985 K. The calorimeter has a mass of 1.500 kg and a specific heat of 2.52 J/g K. What is the heat of reaction for this system? What equation should I use in this case? I've written down these notes: Steps: 1. Calculate the mass of the solution in total. 2. Convert mass to volume or vice versa if needed. 3. Calculate the temperature change of the solution. 4. Calculate the energy released by the reaction.</span>
Answer:
Ionic bonds usually occur between metal and nonmetal ions. For example, sodium (Na), a metal, and chloride (Cl), a nonmetal, form an ionic bond to make NaCl.
Explanation:
The state of atoms in a neon light when light is emitted is loss of energy.
Answer:
4.06 mol H₂O
Explanation:
- 2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O
First we <em>convert the given masses of reactants into moles</em>, using <em>their respective molar masses</em>:
- 250 g O₂ ÷ 32 g/mol = 7.81 mol O₂
- 50 g C₆H₁₄ ÷ 86 g/mol = 0.58 mol C₆H₁₄
Now we <u>calculate how many O₂ moles would react completely with 0.58 C₆H₁₄ moles</u>, using the <em>stoichiometric coefficients of the reaction</em>:
- 0.58 mol C₆H₁₄ *
= 5.51 mol O₂
As there are more O₂ moles than required (7.81 vs 5.51), O₂ is the reactant in excess. That means that <em>C₆H₁₄ is the limiting reactant</em>.
Now we can <u>calculate how much water can be formed</u>, using <em>the number of moles of the limiting reactant</em>:
- 0.58 mol C₆H₁₄ *
= 4.06 mol H₂O
