Ask question

Ask question

All categories

3 years ago

7

How many molecules are in 6.20 moles of CaCO3?

2 answers:

vagabundo [1.1K]3 years ago

8 0

1 mole is equal to 1 moles CaCO3, or 100.0869 grams. hope its right

DedPeter [7]3 years ago

6 0

Answer:

Moles to Grams caco3

1 mole is equal to 1 moles CaCO3, or 100.0869 grams.

You might be interested in

What is pseudo - order reaction

zubka84 [21]

Explanation:

The reactions which are not truly of first order but become reactions of first order under certain conditions are called pseudo first order reactions.

For example, hydrolysis of ester

7 0

2 years ago

Read 2 more answers

Name or write the formula for the following polyatomic ions

Delvig [45]

Answer:

Name Formula

nitrite ion NO2−

permanganate ion MnO4−

phosphate ion PO43−

hydrogen phosphate ion HPO42−

Explanation:

5 0

3 years ago

Creating a prototype and troubleshooting o

lys-0071 [83]

D. a new technology.

6 0

3 years ago

Read 2 more answers

Starting with 2.50 mol of N2 gas (assumed to be ideal) in a cylinder at 1.00 atm and 20.0C, a chemist first heats the gas at con

arsen [322]

Answer:

a) $T_b=590.775k$

b) $W_t=1.08*10^4J$

d) $Q=3.778*10^4J$

d) $\triangle V=4.058*10^4J$

Explanation:

From the question we are told that:

Moles of N2 $n=2.50$

Atmospheric pressure $P=100atm$

Temperature $t=20 \textdegree C$

$t = 20+273$

$t = 293k$

Initial heat $Q=1.36 * 10^4 J$

a)

Generally the equation for change in temperature is mathematically given by

$\triangle T=\frac{Q}{N*C_v}$

Where

$C_v=Heat\ Capacity \approx 20.76 J/mol/K$

$T_b-T_a=\frac{1.36 * 10^4 J}{2.5*20.76 }$

$T_b-293k=297.775$

$T_b=590.775k$

b)

Generally the equation for ideal gas is mathematically given by

$PV=nRT$

For v double

$T_c=2*590.775k$

$T_c=1181.55k$

Therefore

$PV=Wbc$

$Wbc=(2.20)(8.314)(1181_590.778)$

$Wbc=10805.7J$

Total Work-done $W_t$

$W_t=Wab+Wbc$

$W_t=0+1.08*10^4$

$W_t=1.08*10^4J$

c)

Generally the equation for amount of heat added is mathematically given by

$Q=nC_p\triangle T$

$Q=2.20*2907*(1181.55-590.775)\\$

$Q=3.778*10^4J$

d)

Generally the equation for change in internal energy of the gas is mathematically given by

$\triangle V=nC_v \triangle T$

$\triangle V=2.20*20.76*(1181.55-293)k$

$\triangle V=4.058*10^4J$

3 0

2 years ago

A mbxture of iron and sulfur can be separated by attracting the Iron particles with a magnet. If the iron and sulfur mixture is

Alex777 [14]

Answer:

C. homogeneous mixture

4 0

3 years ago