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amid [387]
3 years ago
9

Gold forms face-centered cubic crystals. The atomic radius of a gold atom is 144 pm. Consider the face of a unit cell with the n

uclei of the gold atoms at the lattice points. The atoms are in contact along the diagonal. Calculate the length of an edge of this unit cell.
Chemistry
1 answer:
kipiarov [429]3 years ago
8 0

Answer:

The length of an edge of this unit cell is 407.294 pm

Explanation:

Face centered cubic structure contains 4 atoms in each unit cell and 12 coordination number, occupying about 74% volume of the total cell. Face centered cubic structure is known for efficient use of space for atom packing.

To determine the edge length, a relationship between the radius of the atom and edge length is used.

X = R√8

Where;

X is the length of an edge of this unit cell

R is the radius of the gold atom = 144 pm = 144 X 10⁻¹² m

X = 144 X 10⁻¹²√8

X = 407.294 X 10⁻¹² m

X = 407.294 pm

Therefore, the length of an edge of this unit cell is 407.294 pm

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The number of electron pairs is 4 that means the hybridization will be sp^3 but as there are three bonding domains and one nonbonding domain, thus electronic geometry is tetrahedral and the molecular geometry will be trigonal pyramidal.

Linear electron geometry is possible when number of electron pairs is 2 and the hybridization will be sp^2.

Trigonal planar geometry is possible when number of electron pairs is 3 and the hybridization will be sp^3.

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Different area of the oceans have different salinities.

Salinity is highest at the tropics and equator due to high rate of evaporation and low precipitation.

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Learn more about salinity at: brainly.com/question/20283396

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