Question

The accepted value for the mass of a moonrock is 46.37 g. In an experiment the rock is measured to be 47.25 g. What is the percent error of the measurement?

Answer 1

Answer:

The answer is

2.00 %

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\%$

From the question

actual measurement = 46.37 g

error = 47.25 - 46.37 = 0.88

The percentage error of the measurement is

$P(\%) = \frac{0.88}{46.37} \times 100 \\ = 1.89777873...$

We have the final answer as

2.00 %

Hope this helps you