Answer: The value of
for chloroform is
when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.
Explanation:
Given: Moles of solute = 0.793 mol
Mass of solvent = 0.758

As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.

Now, the values of
is calculated as follows.

where,
i = Van't Hoff factor = 1 (for chloroform)
m = molality
= molal boiling point elevation constant
Substitute the values into above formula as follows.

Thus, we can conclude that the value of
for chloroform is
when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.
Answer:
<h2>The answer is 7.14 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula

From the question
mass of metal = 25 g
volume = final volume of water - initial volume of water
volume = 28.5 - 25 = 3.5 mL
It's density is

We have the final answer as
<h3>7.14 g/mL</h3>
Hope this helps you
<span>The reason it will be 7 for some titrations is that when you titrates a strong acid with a strong base for example HCl and NaOH the salt formed is conjugate base of strong acid and will be a very weak base
That means that it cannot produce any OH^-1 and all the H+ has been converted to water.The only source of H+ or OH is water with a Ka of 10^-14 so the pH = -log [H+]=-log 10^-7 = 7
second reason is
When you titrates a weak acid with strong base at equivalence point
only a water solution of the conjugate base exists
CH3COOH + NaOH ----- Na+ CH3COO^-1 + H2O
Since the conjugate base is the conjugate base of a weak acid it will hydrolyze in water like so
for instance Na+ CH3COO^-1 + HCl---- CH3COOH + NaCl the equivalence point will be way BELOW 7 and in the case of above will be less than 5. So pH of 7 at equivalence point is only reached in strong acid strong base titrations.
hope this helps</span>
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