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Flura [38]
3 years ago
6

What properties of matter are intensive independent of their size

Chemistry
1 answer:
Paha777 [63]3 years ago
8 0

Answer:

temperature, refractive index, density, and hardness of an object

Explanation:

it is a bulk property, meaning that it is a physical property of a system that does not depend on the system size or the amount of material in the system

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How many moles of Ca atoms are in 1 mol of CaSO4?
Galina-37 [17]

Answer:

6.02 x 10²³ atoms

Explanation:

Given parameters:

Number of moles CaSO₄ = 1 mole

Unknown:

Number of Ca atoms in the given compound = ?

Solution:

The given compound is:

          CaSO₄

     1 mole of CaSO₄  is made up of 1 mole of Ca atoms

Now;

   1 mole of any substance contains 6.02 x 10²³ atoms

  1 mole of Ca atoms will also contain 6.02 x 10²³ atoms

7 0
3 years ago
HELP
Jobisdone [24]

Answer:

hello,

first one is 25.15

second is 301.55

Explanation:

honestly if you look up on the internet there is a converter to get you your answers

5 0
3 years ago
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If the theoretical yield of RX is 56.0 g , what is it’s percent yield ?b
Angelina_Jolie [31]
<span>the theoretical yield which is the expected yield and the actual yield obtained are not always the same. therefore percent yield is calculated which shows how much of the percentage of the theoretical yield is actually obtained.
the theoretical yield = 56.0 g 
actual yield = 47.0 g 
percent yield = actual yield / theoretical yield x 100 %
percent yield = 47.0 / 56.0 x 100% = 83.9 %
percent yield = 83.9 %</span>
8 0
3 years ago
Read 2 more answers
What is the independent variable?
olganol [36]
X is always the independent variable
6 0
3 years ago
Consider the following reaction: 2{\rm{ N}}_2 {\rm{O(}}g)\; \rightarrow \;2{\rm{ N}}_2 (g)\; + \;{\rm{O}}_2 (g)
fredd [130]

Answer:

a. 5.9 × 10⁻³ M/s

b. 0.012 M/s

Explanation:

Let's consider the following reaction.

2 N₂O(g) → 2 N₂(g) + O₂(g)

a.

Time (t): 12.0 s

Δn(O₂): 1.7 × 10⁻² mol

Volume (V): 0.240 L

We can find the average rate of the reaction over this time interval using the following expression.

r = Δn(O₂) / V × t

r = 1.7 × 10⁻² mol / 0.240 L × 12.0 s

r = 5.9 × 10⁻³ M/s

b. The molar ratio of N₂O to O₂ is 2:1. The rate of change of N₂O is:

5.9 × 10⁻³ mol O₂/L.s × (2 mol N₂O/1 mol O₂) = 0.012 M/s

4 0
3 years ago
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