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kiruha [24]
3 years ago
11

Could someone help me plz

Mathematics
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

I think it’s c

Step-by-step explanation:

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CAN ANYONE PLEASE HELP ME WITH MY HOMEWORK ILL DO ANYTHING JUST PLEASE HELP ME
nasty-shy [4]

Answer:

9

Step-by-step explanation:

4x9=36

5x9=45

6x9=54

7x9=63

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5 0
3 years ago
Read 2 more answers
The length of one leg of a right triangle is 20.3 centimeters. The length of the hypotenuse is
meriva
<h3>Answer:  Approximately 23.0 cm</h3>

=====================================================

Work Shown:

a = 20.3

b = unknown

c = 30.7

Apply the pythagorean theorem to find b

a^2 + b^2 = c^2

(20.3)^2 + b^2 = (30.7)^2

412.09 + b^2 = 942.49

b^2 = 942.49-412.09

b^2 = 530.4

b = sqrt(530.4)

b = 23.0304146727757  value is approximate

b = 23.0

I rounded to one decimal place because the other values (20.3 and 30.7) were to one decimal place.

8 0
3 years ago
The answer, and work shown.
hoa [83]
Slope= 1/2
Y intercept= (0,2)

Explanation:
Slope-intercept form is y=mx+b
-2x+4y=8
-8-2x=-4y
Divide by -4
2+1/2x=y

Y=1/2x+2
5 0
3 years ago
The probability that a can of paint contains contamination is 3.23%, and the probability of a mixing error is 2.4%. The probabil
stich3 [128]

Answer:

4.6%.

Step-by-step explanation:

The probability that a can of paint contains contamination(C) is 3.23%

P(C)=3.23%

The probability of a mixing(M) error is 2.4%.

P(M)=2.4%

The probability of both is 1.03%.

P(C \cap M)=1.03\%

We want to determine the probability that a randomly selected can has contamination or a mixing error. i.e. P(C \cup M)

In probability theory:

P(C \cup M) = P(C)+P(M)-P(C \cap M)\\P(C \cup M)=3.23+2.4-1.03\\P(C \cup M)=4.6\%

The probability that a randomly selected can has contamination or a mixing error is 4.6%.

3 0
3 years ago
parallel lines r and s are cut by two transversals, parallel lines t and u. Which angles are corresponding angles with angle 8?
Anuta_ua [19.1K]

Option A is correct answer

4 0
3 years ago
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