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kiruha [24]
3 years ago
11

Could someone help me plz

Mathematics
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

I think it’s c

Step-by-step explanation:

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Makayla's local movie theater has a moviegoer club that charges an annual registration fee of $25. However, movie tickets are di
ryzh [129]
The function would have to be the total cost as a function of the number of tickets bought. When you write that in functional notation, that would be C(m). Now, the cost must include the fixed rate of $25 plus a variable rate of $6 per ticket. The function would be,

<em>C(m) = 25 + 6m</em>
8 0
3 years ago
Read 2 more answers
What is 4x-9(-3)=-48?
Ilia_Sergeevich [38]

Answer:

x = 5.25

Step-by-step explanation:

We are given the equation;

4x-9(-3)=-48

Opening the brackets

4x + 27 = 48

Combining the like terms together

4x = 48 -27

4x = 21

Solving for the value of x

x = 21 ÷ 4

  = 5.25

Thus, the value of x is 5.25

6 0
4 years ago
Please help me with this
svet-max [94.6K]

Answer:

∠5  is supplementary.

It forms a straight angle with ∠1.

6 0
3 years ago
A computer sends a packet of information along a channel and waits for a return signal acknowledging that the packet has been re
IRISSAK [1]

Answer:

Step-by-step explanation:

given that a computer sends a packet of information along a channel and waits for a return signal acknowledging that the packet has been received. If no acknowledgment is received within a certain time, the packet is re-sent

Let X represent the number of times the packet is sent. Assume that the probability mass function of X is given by

p(x)={ cx for x=1,2,3,4, or 5

{ 0 otherwise

where c is a constant.

Let us write pdf as follows

x             1              2            3            4           5              Total

p             c             2c           3c         4c         5c              15c

Since total probability = 1

we get

c=\frac{1}{15}

P(X=2)=2c = \frac{2}{15}

7 0
3 years ago
Please help this is holding me back
Likurg_2 [28]
Message me I can help you :)
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3 years ago
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