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kiruha [24]
3 years ago
11

Could someone help me plz

Mathematics
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

I think it’s c

Step-by-step explanation:

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(xy + 2x2y – x2 + 6x3) – (2xy – 6x2y + 4x2 – 6x3) – ( – 2x3 + x2y) + ( – x3 + 4xy + 3x2y – 2x2)
Mazyrski [523]

Answer: =-2(xy-6y-5)

Step-by-step explanation: multiply -(2xy-6 x 2y+ 4 x 2 -6 x 3) remove the parenthesis -2xy + 12 y - 8 +18 calculate -2xy+12y-8+18 factor the expression -2xy + 12y + 10 solution -2 (xy- 6y-5)

3 0
3 years ago
A bag contains a number of marbles of which 35 are blue, 10 are red and the rest are
photoshop1234 [79]

Answer:

Y = 45*p(y) / (1 - p(y))    if I knew what p(y) is, we can find how many yellow marbles there are.   p(y) = probability of choosing yellow.

Step-by-step explanation:

Total marbles =  35 + 10 + yellow

If probability of choosing yellow =p(y) = yellow/Total

p(y) =  Y/(35 + 10 + Y)

Solve for Y,

p(y)*(35 + 10 + Y) = Y

45*p(y) + p(y)*Y = Y

45*p(y) = Y - p(y)*Y

Y = 45*p(y) / (1 - p(y))

7 0
3 years ago
The table shows the number of balls, by sport, in the gym.
n200080 [17]
A. The ratio of soccer balls to all balls are 4:25

All the balls combined are 50 balls

8 of the balls are soccer balls so that makes the ration 8:50

In the simplest form it is 4:25 since you can't divide 4 or 8 by 50, you can use 2
and you get 4:25 as your answer
So it is A.
8 0
3 years ago
Read 2 more answers
Add the following fractions, and give your answer as a reduced improper fraction. 11/13+4/7
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Answer:

Step-by-step explanation:

Give the fractions a common denominator

11/13 + 4/7 = 77/91 + 52/91

= 129/91

8 0
3 years ago
Let v(t)=t2−2tv(t)=t2−2t be the velocity, in feet per second, of an object at time tt, in seconds.
kirza4 [7]
Thee function is given as:

<span>v(t)=t^2−2tv(t)=t^2−2t 

</span>(a) What is the initial velocity? 

Base from the function, the initial velocity would be zero.

(b) When does the object have a velocity of zero?

It would be during time zero. Also, at a time equal to two.
6 0
3 years ago
Read 2 more answers
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