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Vika [28.1K]
3 years ago
9

CH4 and CO₂ are the chemical formulas for:

Chemistry
1 answer:
nadya68 [22]3 years ago
6 0

Answer:

CH4 = Methane

CO2 = Carbon dioxide

<h3>Hope this Helps!!</h3><h3>Hope this Helps!!:)</h3>
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How many moles are in 454 Liters of a gas?
Natalka [10]

Answer:

20.27 mol

Explanation:

454 L x (1 mol/22.4 L) = 20.27 mol

3 0
3 years ago
"whenever a stress is applied to a system at equilibrium, the equilibrium shifts in such way as to undo the effect of the stress
Nady [450]
IDK I JUST NEED POINTS, BTW IM VERY DUMB
3 0
3 years ago
You heat 3.869 g of a mixture of fe3o4 and feo to form 4.141 g fe2o3. What is the mass of oxygen reacted?
Lostsunrise [7]

The reaction is  

FeO + Fe3O4 + 1/2 O2---> 2Fe2O3

Thus as shown in the balanced equation two moles of Fe2O3 are formed when 0.5 moles of O2 reacted with mixture of FeO and Fe3O4

moles of Fe2O3 = MAss / Molar mass = 4.141 / 159.69 = 0.0259 moles

So moles of O2 needed = 0.5 X 0.0259 = 0.01295

Mass of O2 = moles X molar mass = 0.01295 X 32 = 0.4144 grams

5 0
3 years ago
How many seconds does it take a race horse to run six furlongs at 40.7 miles per hour if: I furlong = 40 rods; 5.5 yards = 1 rod
lana [24]

Distance traveled by the race horse=6 furlongs

Converting the distance from furlongs to rods: 40 rods =1 furlong

6 furlongs*\frac{40rods}{1furlong} =240rods

Converting the distance from rods to yards, feet and miles: 5.5 yards = 1 rod, 3foot =1 yard, 1 mile = 5280 feet.

240rods*\frac{5.5yards}{1rod}*\frac{3foot}{1yard}*\frac{1mi}{5280feet}=0.75mi

The given speed of race horse = 40.7mi/hr

Calculating the time required:

0.75mi*\frac{1hr}{40.7mi}*\frac{60min}{1hr}*\frac{60s}{1min}= 66.34s

Therefore, 66.34 s is required for a race horse to run six furlongs at 40.7 miles per hour.

8 0
3 years ago
Help Please!!!!!!!!!!!!!!!!!!!!!!
RUDIKE [14]

Answer:

B

Explanation:

7 0
3 years ago
Read 2 more answers
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