Answer:
Explanation:
Molar mass of sodium hydroxide is = 100
any compund with its molar mass dissovled in 1L itres solution gives rise to 1M solution
40 g ------> 1L ---->1M
Xg ------>1L------>2M
X g= 40*1*2/1*1 =80 gram
Answer:
The answer is in the explanation.
Explanation:
The KHP is an acid used as standard in titrations to find concentration of bases as NaOH.
The reaction that explain this use is:
KHP + NaOH → KNaP + H2O
<em>where 1 mole of KHP reacts per mole of NaOH</em>
That means, at equivalence point of a titration in which titrant is NaOH, the moles of KHP = Moles of NaOH added
With the moles of KHP = Moles of NaOH and the volume used by titrant we can find the molar concentration of NaOH.
The moles of KHP are obtained from the volume and the concentration as follows:
Volume(L)*Concentration (Molarity,M) = moles of KHP
If the concentration is more or less than 0.100M, the moles will be higher or lower. For that reason, we need to know the concentration of KHP but is not necessary to be 0.100M.
<u>Given:</u>
Mass of H2O2 solution = 5.02 g
Mass of H2O2 = 0.153 g
<u>To determine: </u>
The % H2O2 in solution
<u>Explanation:</u>
Chemical reaction-
2H2O2(l) → 2H2O(l) + O2(g)
Mass % of a substance in a solution = (Mass of the substance/Mass of solution) * 100
In this case
% H2O2 = (Mass H2O2/Mass of solution)* 100 = (0.153/5.02)*100 = 3.05%
Ans: % H2O2 in the solution = 3.05%
Answer:3 moles
Explanation:
For every three molecules of CO2 that enters the Calvin cycle, one molecule of the three carbon glyceraldehyde 3-phosphate (G3P) is produced. Two molecules of G-3-P are required to produce one molecule of glucose. Therefore, the Calvin cycle needs to make a total of 6 turns to produce two molecules of G-3-P.
