The current passing through the inductor is 3.8 A. The correct option is D. 3.8 A
<h3>Energy stored in a magnetic field </h3>
From the question, we are to determine the current passing through the inductor.
From the formula, for the energy stored in a magnetic field
E = 1/2LI²
Where E is the energy
L is the inductance
and I is the current
From the given information,
E = 3.6 J
L = 0.50 H
Putting the parameters into the formula, we get
3.6 = 1/2 × 0.50 × I²
3.6 = 0.25 × I²
I² = 3.6 ÷ 0.25
I² = 14.4
I = √14.4
I = 3.7947
I ≅ 3.8 A
Hence, the current passing through the inductor is 3.8 A. The correct option is D. 3.8 A
Learn more on Energy stored in a magnetic field here: brainly.com/question/15244801
We are given with a vinegar with a hydrogen ion concentration of 0.00010 m. We are asked to express this concentration in scientific notation. The answer when expressed in scientific notation is 1x10^-4 m or molality. Answer is <span>1x10^-4 m. </span>
Answer:
C15 H31 O4 S
Explanation:
molecular formula is also the same because the value of "n" is 1
Answer: from the Zn anode to the Cu cathode
Justification:
1) The reaction given is: Zn(s) + Cu₂⁺ (aq) -> Zn²⁺ (aq) +Cu(s)
2) From that, you can see the Zn(s) is losing electrons, since it is being oxidized (from 0 to 2⁺), while Cu²⁺, is gaining electrons, since it is being reduced (from 2⁺ to 0).
3) Then, you can already tell that electrons go from Zn to Cu.
4) The plate where oxidation occurs is called anode, and the plate where reduction occus is called cathode.
So you get that the electrons flow from the anode (Zn) to the cathode (Cu).
Always oxidation occurs at the anode, and reduction occurs at the cathode.
