
or

Answer:
Solution given:
y=2x²-5x+6.....[1]
y=3x+3.........….[2]
solving equation 1&2
2x²-5x+6=3x+3
2x²-5x-3x+6-3=0
2x²-8x+3=0
comparing above equation with ax²+bx+c=0 we get
a=2
b=-8
c=3
by using quadratic equation


taking positive


taking negative

Answer:
you have to add them together
Answer:
Quadrant 4
Step-by-step explanation:
Answer:
Step-by-step explanation:
These triangles are similar triangles, so there is a number that you can multiply the sides of TUV to find the side lengths of QRS. looking at the triangle, the similar sides are RS being similar to UV and RQ being similar to UT.
If RS~UV, then there is a ratio between them. 54/36=1.5. The ratio is 1.5.
RQ~UT, and by a factor of 1.5, so divide RQ by the scale factor. 24/1.5=16. UT=16=x+5.
x+5=16, subtract 5 from both sides.
x=11