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yulyashka [42]
3 years ago
6

A train increases speed from 10 m/s to 20 m/s. What is the average speed while increasing the speed? And how far dies it travel

while increasing the speed?
Physics
2 answers:
Tanya [424]3 years ago
7 0

Explanation:

average speed =(first velocity + second velocity)/2

=(10 +20)/2=15m/s

distance=average speed × time

= 15 × t ( but time not given)

Akimi4 [234]3 years ago
6 0
Ok so basically.. and then if you.. you get …
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Answer:

Short circuit

Explanation:

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A proposed space elevator would consist of a cable stretching from the earth's surface to a satellite, orbiting far in space, th
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To solve this problem we will apply the concepts related to energy conservation. Here we will use the conservation between the potential gravitational energy and the kinetic energy to determine the velocity of this escape. The gravitational potential energy can be expressed as,

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KE= \frac{1}{2} mv^2

Where,

G = 6.67*10^{-11}m^3/kg\cdot s^2Gravitational Universal Constant

m = 5.972*10^{24}kg Mass of Earth

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Rearranging to find the velocity,

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If the height of the satellite from the earth is h, then the total distance would be the radius of the earth and the eight,

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Replacing the values we have that

v = \frac{2(6.67*10^{-11})(5.972*10^{24})}{6.378*10^6+56*10^6}

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3 years ago
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3 years ago
Read 2 more answers
A train is moving at 15ms-1. It slows down to 10.5ms over a time of 4s. Calculate the distance it travels before stopping if acc
Morgarella [4.7K]

Answer:

(v2 - v1) / t = a for uniform acceleration

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S = V0 T + 1/2 a T^2

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8 0
3 years ago
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