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Zepler [3.9K]
3 years ago
12

An Olympic diver is on a diving platform 8.60 m above the water. To start her dive, she runs off of the platform with a speed of

1.23 m/s in the horizontal direction. What is the diver's speed (the sum of her horizontal and vertical velocities), in m/s, just before she enters the water?
Physics
1 answer:
Ronch [10]3 years ago
6 0

Answer:

13.1 m/s

Explanation:

If we assume that there is not air resistance then the horizontal component of velocity remains constant.  That is 1.23 m/s

The vertical component of final velocity can be calculated the following way:

v_{yf} ^{2} =v_{yi}^{2}  +2ax\\

v_{yf} = \sqrt{1.23^{2}+2*9.81*8.60} = 13.0 m/s

So the final velocity will be the square root of the sum of the squares of the component

v² = 1.23² + 13.0²

v = 13.1 m/s

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An aluminum cylinder weighing 30 N, 6 cm in diameter and 40 cm long, is falling concentrically through a long vertical sleeve of
Georgia [21]

Answer: Velocity terminal = 0.093m/s

Explanation:

1. We start by evaluating the gap distance between the two cylinders as h = R(sleeve) - R(cylinder)

= (0.0604/2 - 0.06/2)m

= 2×10^-4

Surface are of the cylinder in the drop, which is required in order to evaluate the shearing stress can be expressed as A(cylinder) = π.d.L

= (π×0.06×0.4)m²

= 0.075m²

Since the force of the cylinder's weight is going to balance the shearing force on the walls, we can express the next equation and derive terminal velocity from it.

Shearing stress = u×V.terminal/h = 0.86×V/0.0002

= 4300Vterminal

Therefore, Fw = shearing stress × A

30N = 4300Vterminal × 0.075

V. terminal = 30/4300 m.s

V. terminal = 0.093m/s

4 0
3 years ago
Lightning is an example of what kind of electricity
ki77a [65]

the answer would be DISCHARGE

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7 0
3 years ago
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Assume that the driver begins to brake the car when the distance to the wall is d=107m, and take the car's mass as m-1400kg, its
Evgen [1.6K]

Answer:

Explanation:

a ) Let let the frictional force needed be F

Work done by frictional force = kinetic energy of car

F x 107 = 1/2 x 1400 x 35²

F = 8014 N

b )

maximum possible static friction

= μ mg

where μ is coefficient of static friction

= .5 x 1400 x 9.8

= 6860 N

c )

work done by friction for μ = .4

= .4 x 1400 x 9.8 x 107

= 587216 J

Initial Kinetic energy

= .5 x 1400 x 35 x 35

= 857500 J

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= 857500 - 587216

= 270284 J

So , if v be the velocity at the time of collision

1/2 mv² = 270284

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d ) centripetal force required

= mv₀² / d which will be provided by frictional force

= (1400 x 35 x 35) / 107

= 16028 N

Maximum frictional force possible

= μmg

= .5 x 1400 x 9.8

= 6860 N

So this is not possible.

4 0
3 years ago
A hydraulic lift raises 1140 kg car through a height of 2.4 m. What is the potential energy
Sladkaya [172]
1140x9.8x2.4= 26,812.8 significant figures Make it 27,000
5 0
2 years ago
What kind of organisms are able to convert sunlight into usable energy?
Tamiku [17]

Answer:

Photosynthetic organisms

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Hope this helps! :)

4 0
3 years ago
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