Question

An Olympic diver is on a diving platform 8.60 m above the water. To start her dive, she runs off of the platform with a speed of 1.23 m/s in the horizontal direction. What is the diver's speed (the sum of her horizontal and vertical velocities), in m/s, just before she enters the water?

Answer 1

Answer:

13.1 m/s

Explanation:

If we assume that there is not air resistance then the horizontal component of velocity remains constant.  That is 1.23 m/s

The vertical component of final velocity can be calculated the following way:

$v_{yf} ^{2} =v_{yi}^{2} +2ax$

$v_{yf} = \sqrt{1.23^{2}+2*9.81*8.60} = 13.0 m/s$

So the final velocity will be the square root of the sum of the squares of the component

v² = 1.23² + 13.0²

v = 13.1 m/s