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Zepler [3.9K]
3 years ago
12

An Olympic diver is on a diving platform 8.60 m above the water. To start her dive, she runs off of the platform with a speed of

1.23 m/s in the horizontal direction. What is the diver's speed (the sum of her horizontal and vertical velocities), in m/s, just before she enters the water?
Physics
1 answer:
Ronch [10]3 years ago
6 0

Answer:

13.1 m/s

Explanation:

If we assume that there is not air resistance then the horizontal component of velocity remains constant.  That is 1.23 m/s

The vertical component of final velocity can be calculated the following way:

v_{yf} ^{2} =v_{yi}^{2}  +2ax\\

v_{yf} = \sqrt{1.23^{2}+2*9.81*8.60} = 13.0 m/s

So the final velocity will be the square root of the sum of the squares of the component

v² = 1.23² + 13.0²

v = 13.1 m/s

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