Based on the cost of the furniture, the following are true:
- a. $10,400.
- b. $93,600
- c. $20,800
<h3>Depreciation in second year</h3>
Depreciation per year = (Cost of furniture - Salvage value) / Useful life
Cost will include both the purchase price and the charge for insurance and shipping.
= (100,000 + 12,000 - 8,000) / 10
= $10,400
<h3>BV at end of first year</h3>
= Cost - Depreciation
= 104,000 - 10,400
= $93,600
<h3>BV after 8 years </h3>
= Cost - (Depreciation x 8 years )
= 104,000 - (10,400 x 8)
= $20,800
In conclusion, depreciation is $10,400 per year.
Find out more about SL depreciation at brainly.com/question/13734742.
Answer:
total time = 304.21 s
Explanation:
given data
y = 50% = 0.5
n = 1.1
t = 114 s
y = 1 - exp(-kt^n)
solution
first we get here k value by given equation
y = 1 - 
...........1
put here value and we get
0.5 = 1 - e^{(-k(114)^{1.1})}
solve it we get
k = 0.003786 = 37.86 × 
so here
y = 1 -
1 - y =
take ln both side
ln(1-y) = -k × 
so
t = ![\sqrt[n]{-\frac{ln(1-y)}{k}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7B-%5Cfrac%7Bln%281-y%29%7D%7Bk%7D%7D)
.............2
now we will put the value of y = 87% in equation with k and find out t
t = ![\sqrt[1.1]{-\frac{ln(1-0.87)}{37.86*10^{-4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B1.1%5D%7B-%5Cfrac%7Bln%281-0.87%29%7D%7B37.86%2A10%5E%7B-4%7D%7D%7D)
total time = 304.21 s
Explanation:
i think option 4 is correct answer because itsrelated to animal not plants.
Answer:
<em>Object-oriented</em>
Explanation:
<em>Object Oriented programming</em> <em>(OOP)</em> is a specific way of programming, where the code is organized in units called classes, from which objects are created that are related to each other to achieve the objectives of the applications. Object-oriented programming took over as the dominant programming style in the mid-1980s, largely due to the influence of C ++. Its dominance was consolidated thanks to the rise of graphical user interfaces, for which object-oriented programming is particularly well suited. Its most important characteristics are the following:
