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lora16 [44]
4 years ago
7

Consider an open loop 1-degree-of-freedom mass-spring damper system. The system has mass 4.2 kg, and spring stiffness of 85.9 N/

m, and damping coefficient of 1.3 N.s/m. What is the non-dimensional damping ratio of the system? Use at least 4 significant digits after the decimal point.
Engineering
1 answer:
Marat540 [252]4 years ago
3 0

Answer:

Damping ratio  \zeta =0.0342

Explanation:

Given that

m=4.2 kg,K=85.9 N/m,C=1.3 N.s/m

We need to find damping ratio

We know that critical damping co-efficient

 C_c=2\sqrt {mk}

 C_c=2\sqrt {4.2\times 85.9}

 C_c=37.98 N.s/m

Damping ratio(\zeta) is the ratio of damping co-efficient to the critical damping co-efficient

So \zeta =\dfrac{C}{C_c}

\zeta =\dfrac{1.3}{37.98}

\zeta =0.0342

So damping ratio  \zeta =0.0342

 

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