Answer:
Yes equation is valid.
Explanation:
Given:
h = (0.04 to 0.09)(D/d)^4*V^2/2*g
Using SI units to assign dimensions to every quantity as follows:
Energy loss per unit weight h = J / N = kg m ^2 s^-2 / kg m s^-2 = [m]
Hose diameter D = [m]
Nozzle tip diameter d = [m]
Fluid velocity in the hose V = [ m s^-1 ]
Acceleration of gravity g = [ m s^-2 ]
Using the Given Equation and plug the SI units of respective quantities:
h = (0.04 to 0.09)(D/d)^4*V^2/2*g
[m] = (0.04 to 0.09)([m] / [m])^4*[ m s^-1 ]^2/2*[ m s^-2 ]
Simplify the equation above:
[m] = ( 1 )^4 * [ m^2 s^-2 ] / [ m s^-2 ]
[m] = [m]
Hence, SI units of RHS of given equation = LHS of given equation, we can say the equation has consistent dimensions.
Explanation:
This means that for every 1 cm on the drawing, there is 80 cm in reality. To put it another way, take this
1:80 means that the building is 80 times the size of the drawing
80:1 means that the drawing is 80 times the size of the building
If it were 80:1, the drawing itself would be over 100m long.
Answer:
Only Technician B is right.
Explanation:
The cylindrical braking system for a car works through the mode of pressure transmission, that is, the pressure applied to the brake pedals, is transmitted to the brake pad through the cylindrical piston.
Pressure applied on the pedal, P(pedal) = P(pad)
And the Pressure is the applied force/area for either pad or pedal. That is, P(pad) = Force(pad)/A(pad) & P(pedal) = F(pedal)/A(pedal)
If the area of piston increases, A(pad) increases and the P(pad) drops, Meaning, the pressure transmitted to the pad reduces. And for most cars, there's a pressure limit for the braking system to work.
If the A(pad) increases, P(pad) decreases and the braking force applied has to increase, to counter balance the dropping pressure and raise it.
This whole setup does not depend on the length of the braking lines; it only depends on the applied force and cross sectional Area (size) of the piston.
Answer: The electric field decreases because of the insertion of the Teflon.
Explanation:
If the charge on the capacitor is held fixed, the electric field as a consequence of this charge distribution (directed from the positive charged plate to the negative charged one remains unchanged.
However, as the Teflon is a dielectric material, even though doesn't allow the free movement of the electrons as an answer to an applied electric field, it allows that the electrons be displaced from the equilibrium position, leaving a local negative-charged zone close to the posiitive plate of the capacitor, and an equal but opposite charged layer close to the negative plate.
In this way, a internal electric field is created, that opposes to the external one due to the capacitor, which overall effect is diminishing the total electric field, reducing the voltage between the plates, and increasing the capacitance proportionally to the dielectric constant of the Teflon.
